2Na + 2H2O -------> 2NaOH + H2
Since the given reaction is already balanced, simply divide 12 by the coefficient of Na in the equation, resulting in a quotient of 6. Multiply the coefficients of the original equation by 6 to obtain the answer: 6 X 2 = 12 moles of water required. (Note that the equation should have been written with mostly capital letters as follows: 2 Na + 2 H2O -> 2 NaOH + H2.)
The reaction is:2 Na + 2 H2O = 2 NaOH + H2
2Na + 2 HNO3 = 2 NaNO3 + H2
Water doesn't dissolve sodium, water react violently with sodium:2 Na + 2 H2O = 2 NaOH + H2
2Na + 2H2O -------> 2NaOH + H2
All you gotta do is make sure that theres equal amounts of a particular element on each side, eg. 2 sodium on the left, thus there needs to be 2 on the right. 2 Na + 2H2O ----> 2 NaOH + H2
2Na + 2H2O -> H2 + 2NaOH
Na + H2O --> NaOH + H2
It has been a long time, but I think it has to read: 2Na + 2H2O --> 2NaOH + H2 to be balanced.
bromine water? The reaction between hexene, bromine, and water is an addition reaction.
NaOH + H2O ---> Na+(aq) + OH-(aq) + H2O or in Net Ionic terms NaOH ----> Na+(aq) + OH-(aq) There is no reaction. NaOH only ionizes.
Yes, the water and sodium produce sodium hydroxide and hydrogen!
2Na + 2H2O = 2NaOH + H2 2Na + 2HCl = 2NaCl + H2 Na+H2O= NaOH2
4Na + O2 = 2Na2O The reactants are the sodium (Na) and the oxygen (O2) NB The product is Na2O
Since the given reaction is already balanced, simply divide 12 by the coefficient of Na in the equation, resulting in a quotient of 6. Multiply the coefficients of the original equation by 6 to obtain the answer: 6 X 2 = 12 moles of water required. (Note that the equation should have been written with mostly capital letters as follows: 2 Na + 2 H2O -> 2 NaOH + H2.)
2 Na + 2 H2O > 2 NaOH + H2