It can refer to binary numbers or a vast variety of things. Please ask this question again using words that indicate what you want to know. Ensure you put it in the correct category to get a meaningful answer.
Take any number, we will refer to that number as n. Now: -n+n=0 For example: -1+1=0
Excess-3 BCD a B c d w x y z 0 0 1 1 0 0 0 0 0 1 0 0 0 0 0 1 0 1 0 1 0 0 1 0 0 1 1 0 0 0 1 1 0 1 1 1 0 1 0 0 1 0 0 0 0 1 0 1 1 0 0 1 0 1 1 0 1 0 1 0 0 1 1 1 1 0 1 0 1 0 0 0 1 0 0 0 1 0 0 1 i'm not sure. but it should be the ans
a b c y 0 0 0 0 0 0 0 1 0 0 1 0 0 0 1 1 0 1 0 0 0 1 0 1 0 1 1 0 0 1 1 1 1 0 0 0 1 0 0 1 1 0 1 0 1 0 1 1 1 1 0 0 1 1 0 1 1 1 1 0 1 1 1 1 FORMULA FOR possibilities = 2 ^(no of variables). Here its 4 so, 2n=24=16 Hence we have 16 possibilities.
w x y z 0 0 0 0 0 0 0 1 0 0 1 0 0 0 1 1 0 1 0 0 0 1 0 1 0 1 1 0 0 1 1 1 1 0 0 0 1 0 0 1 1 0 1 0 1 0 1 1 1 1 0 0 1 1 0 1 1 1 1 0 1 1 1 1 FORMULA FOR possibilities = 2 ^(no of variables). Here its 4 so, 2n=24=16 Hence we have 16 possibilities.
0 . . . 0 0 0 0 1 . . . 0 0 0 1 2 . . . 0 0 1 0 3 . . . 0 0 1 1 4 . . . 0 1 0 0 5 . . . 0 1 0 1 6 . . . 0 1 1 0 7 . . . 0 1 1 1 8 . . . 1 0 0 0 9 . . . 1 0 0 1 10 . . 1 0 1 0 11 . . 1 0 1 1 12 . . 1 1 0 0 13 . . 1 1 0 1 14 . . 1 1 1 0 15 . . 1 1 1 1 16. 1 0 0 0 0 . . etc.
11
0 . . . . . 0 0 0 0 1 . . . . . 0 0 0 1 2 . . . . . 0 0 1 0 3 . . . . . 0 0 1 1 4 . . . . . 0 1 0 0 5 . . . . . 0 1 0 1 6 . . . . . 0 1 1 0 7 . . . . . 0 1 1 1 8 . . . . . 1 0 0 0 9 . . . . . 1 0 0 1 10 . . . . 1 0 1 0
1 0 1 0 0 1 0 1 0 1 1 0 1 1 0 1 0 1 1 1 1 1 0 0 0 1 1 0 0 1
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AND A B Q 0 0 0 0 1 0 1 0 0 1 1 1 OR A B Q 0 0 0 0 1 1 1 0 1 1 1 1 NOT A Q 0 1 1 0 (I might as well carry on) XOR A B Q 0 0 0 0 1 1 1 0 1 1 1 0 NAND A B Q 0 0 1 0 1 1 1 0 1 1 1 0 NOR A B Q 0 0 1 0 1 0 1 0 0 1 1 1 BUF (NNOT) A Q 0 0 1 1 XNOR A B Q 0 0 1 0 1 0 1 0 0 1 1 1
it can refer to anything that has to do with the role of people in the development 0:0
Strobe A B C D Output (Y) 0 0 0 0 0 D0 0 0 0 0 1 D1 0 0 0 1 0 D2 0 0 0 1 1 D3 0 0 1 0 0 D4 0 0 1 0 1 D5 0 0 1 1 0 D6 0 0 1 1 1 D7 0 1 0 0 0 D8 0 1 0 0 1 D9 0 1 0 1 0 D10 0 1 0 1 1 D11 0 1 1 0 0 D12 0 1 1 0 1 D13 0 1 1 1 0 D14 0 1 1 1 1 D15 1 X X X X 1 where A,B,C,D are the control input or control nibble and the Boolean expression for Y is given as:- Y = A'B'C'D'D0 + A'B'C'DD1 + A'B'CD' D2 + A'B'CDD3 + A'BC'D'D4 + A'BC'DD5+ A'BCD'D6 + A'BCDD7 + AB'C'D'D8 + AB'C'DD9 + AB'CD'D10 + AB'CDD11 + ABC'D'D12 + ABC'DD13 + ABCD'D14 + ABCDD15