The formula for calculating the TOTAL of the interior angles of an n-sided polygon is:
Angle Sum = 180 (n-2) degrees
So for a regular polygon, each of the identical interior angles will be 180(n-2)/n
The equivalent formula is 180 - (360/n), where 360/n is a single exterior angle, supplementary.
How many sides does a regular polygon have if the measure of each interior angle is equal to 172 degress ?
The polygon with the largest interior angle is a regular polygon, specifically a regular polygon with the greatest number of sides. In a regular polygon, all interior angles are equal, and the formula for calculating the interior angle of a regular polygon is (n-2) * 180 / n, where n is the number of sides. As the number of sides increases, the interior angle also increases. Therefore, a regular polygon with a very large number of sides will have the largest interior angle.
A 16 sided polygon.
A regular polygon has sides of equal length and each interior angle is the same measure
The polygon will have 12 equal sides and each interior angle measures 150 degrees.
Each interior angle of a regular polygon has a measure that is equal to one hundred and eighty degrees times two less than the number of sides in the polygon.
It will have 10 equal sides
For a regular polygon with sides n, the sum of the interior angles = (n-2)180Therefore, a regular polygon has interior angle sum equal to 540o.(5-2)180=(3)180=540
A regular hexagon which has 6 equal sides and 6 equal angles.
The equation for finding the interior angle measures of a regular n-gon is (n-2)*180/n. Thus, if this is set equal to 176 and solved for n, n is found to be 90. Therefore, a regular polygon with each interior angle measure equal to 176, has 90 sides.
Five. It is a regular pentagon.
6 sides and it is a regular hexagon