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In point-slope form of a linear equation, which is expressed as (y - y_1 = m(x - x_1)), the letter (b) typically represents the y-intercept of the line when the equation is rewritten in slope-intercept form (y = mx + b). However, in the context of point-slope form itself, (b) is not directly used; instead, the focus is on the slope (m) and a specific point ((x_1, y_1)) on the line.
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Example of a slope intercept form?
Slope intercept form is y=mx+b the m would stand for your slope and b would stand for you y intercept written as (0,b)
How do you write anequation in point slope form?
Given a point P(a,b) and slope m, the point slope equation is (y - b)/(x - a) = m
What is point slope form and slope intercept form?
y=mx+b is slope-intercept form y - y1 = m(x - x1) is point-slope form Used in algebra based math. On a graph; m is the slope b is the y-intercept x and y represent points
What is point slope form of an equation of a line?
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
What is the difference between slope-intercept form and point-slope form?
Slope-intercept form (y = mx + b) expresses a linear equation in terms of the slope (m) and the y-intercept (b), making it easy to identify these key features directly from the equation. In contrast, point-slope form (y - y₁ = m(x - x₁)) focuses on a specific point (x₁, y₁) on the line and the slope (m), which is useful for writing the equation when a point and the slope are known. Essentially, slope-intercept form is best for graphing, while point-slope form is ideal for deriving equations from given points.
Example of a slope intercept form?
Slope intercept form is y=mx+b the m would stand for your slope and b would stand for you y intercept written as (0,b)
How do you write anequation in point slope form?
Given a point P(a,b) and slope m, the point slope equation is (y - b)/(x - a) = m
What is point intercept form?
Point slope? y=mx+b M being the slope, and b being the y-intercept.
What is point slope form and slope intercept form?
y=mx+b is slope-intercept form y - y1 = m(x - x1) is point-slope form Used in algebra based math. On a graph; m is the slope b is the y-intercept x and y represent points
How do you change point-slope to slope-intercept?
Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.
What is point slope form of an equation of a line?
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
What is the general form of a line written in slope-intercept form?
It is: y = mx+b whereas m is the slope and b is the y intercept
What are the pieces of slope intercept form?
Slope-Intercept Form is y=mx+b. m=slope and b=y-intercept. The y and x stand for the x and y coordinates in an ordered pair (x,y).
Why is the equation ymx b called the slope-intercept form?
y=m*x+b is called the slope-intercept form because it describes a line where m is the slope and b is the point on the y-axis that the line intercepts.
How do you write a line in point-slope form?
The equation of a line passing through a point P with coordinates (a,b) and slope m is (y-b) = m(x-a) changing that to the more conventional form: y = mx + (b - ma)
Write an equation of the line that has a slope of 3 and contains the point 2 5 in point-slope form?
Point on line = (2,5), therefore, x = 2 and y = 5 Slope = 3 Slope-intercept = ? Slope-intercept form: y = mx + b, where m = slope and b = y-intercept. y = mx + b; Solve for b: 5 = 3(2) + b 5 = 6 + b -6 + 5 = 6 + b -6 -1 = b So the equation of the line is y = 3x -1
What is the slope intercept form of the equation for the line that passes through the point (-10-6) and has a slope of -1?
The slope-intercept form of a line is given by the equation ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope ( m = -1 ) and a point (-10, -6), we can substitute these values into the equation to find ( b ): [ -6 = -1(-10) + b \implies -6 = 10 + b \implies b = -16. ] Thus, the slope-intercept form of the line is ( y = -x - 16 ).
