Point on line = (2,5), therefore, x = 2 and y = 5
Slope = 3
Slope-intercept = ?
Slope-intercept form: y = mx + b, where m = slope and b = y-intercept.
y = mx + b; Solve for b:
5 = 3(2) + b
5 = 6 + b
-6 + 5 = 6 + b -6
-1 = b
So the equation of the line is y = 3x -1
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Choose the equation of the line that contains the points (1, -1) and (2, -2).
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
Equation: y-3 = -5(x-6) => y = -5x+33
If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
y = 2x + 1.
The answe iss..... 6
y = 2x - 1
It is: y = 2x-6
y=2x+1
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
Choose the equation of the line that contains the points (1, -1) and (2, -2).
It is: y-7 = 2(x-3) => y = 2x+1
As a straight line equation: y = -3x+18 in slope intercept form
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33