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Point on line = (2,5), therefore, x = 2 and y = 5

Slope = 3

Slope-intercept = ?

Slope-intercept form: y = mx + b, where m = slope and b = y-intercept.

y = mx + b; Solve for b:

5 = 3(2) + b

5 = 6 + b

-6 + 5 = 6 + b -6

-1 = b

So the equation of the line is y = 3x -1

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Q: Write an equation of the line that has a slope of 3 and contains the point 2 5 in point-slope form?
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