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20 n in a d?
20 Nickels in a Dollar
Write a program to print automorphic numbers between 1 and 100?
import java.math.*; import java.util.*; class AutomorphicNumber{ static int d=10; public static void main(String args[]){ System.out.print("Enter any number :"); Scanner input=new Scanner(System.in); int n=input.nextInt(); if(d>=n){ if ((n*n) % d == n){ System.out.println("Automorphic Number"); } else{ System.out.println("Not Automorphic Number"); } } else if(d<=n){ d=d*10; if ((n*n) %d==n){ System.out.println("Automorphic Number"); } else{ System.out.println("not an automorphic number"); } } } }
Turbo c program that will determine if the input is odd or even number?
#include <stdio.h> int main() { printf("Program to find ODD or Even Number\n"); while(1) { int n = 0; printf("\nEnter a number(-1 for Exit): "); scanf("%d",&n); if( n 0) { printf("%d is a EVEN number.\n", n); } else { printf("%d is a ODD number.\n", n); } } return 0; }
What is the formula to find sum of n even numbers?
Sum = n/2[2Xa1+(n-1)d] where n is last number, a1 is the first number & d is the common difference between the numbers, here d=2 for the even /odd numbers. Sum = n/2 [2Xa1+(n-1)2]
Write a java program to check a number is Armstrong number?
import java.io.*; public class Jerry { public static void main(String as[]) throws IOException { int k=Integer.parseInt(as[0]); int n=k; int d=0,s=0; while(n>0) { d=n%10; s=s+(d*d*d); n=n/10; } if(k==s) System.out.println("Armstrong number"); else System.out.println("not Armstrong number"); } }
Where d is the number of diagonals of a polygon with n sides find d if n equals 20?
1/2*(n2-3n) = number of diagonals 1/2*(202-60) = 170 diagonals
20 n in a d?
20 Nickels in a Dollar
How would you model the phrase 8 times a number n?
The phrase '8 times a number n' just means '8 times n', which can be modeled as 8 x n or 8n.
Make a program that will accept any number n between 20-50 and another number x between 1-5 Then the program will display all numbers from 1-n that is divisible by x?
/* a number divisible by x should be a multiple of x */ int i, n,x; scanf ("%d", &n); scanf ("%d",&x); for(i=x;i =< n;i+=x) { printf ("%d", x); }
How many is 20 percent?
20% of n = .2 * n, where n is a number.
20 N on a D B?
20 numbers on a dartboard
What is the sum of 20 divided by a number and that number divided by 20?
1
What is The sum of 20 and a number is 30?
Let the unknown number be n.Then 20 + n = 30 : Subtract 20 from both sides gives :-20 - 20 + n = 30 - 20 : n = 10
20 percent of the number is 3 find the number?
20% of a number, n, is equal to 3. 0.20 * n = 3 n = 3 / 0.20 = 15 20% of 15 is 3.
Where d is the number of diagonals of a polygon with n sides find d if equals 20?
1/2*(n2-3n) = number of diagonals 1/2*(202-60) = 170 diagonals
A faction in witch the numbers is greater than or equal to the denominator?
Suppose the number is n/d. Then n/d >= d => n <= d2 if d < 0 or n >= d2 if d > 0.
When 3 times a certain number n is add to 6 the sum is 20 more then a origina number what is the number n?
In mathematical terms the problem is :- 3n + 6 = 20 + n 3n - n = 20 - 6 2n = 14 n = 7
