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Sum = n/2[2Xa1+(n-1)d] where n is last number, a1 is the first number & d is the common difference between the numbers, here d=2 for the even /odd numbers. Sum = n/2 [2Xa1+(n-1)2]

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15y ago

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The sum of the first n even number is n*(2+2n)/2 = n(n+1)

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14y ago
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Q: What is the formula to find sum of n even numbers?
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