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What does slope of velocity time graph of uniformly accelerated body represents?
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What can you say about the motion of a body if it's velocity-time graph is a straight line inclined with the time-axis?
uniformly accelerated motion
What can you conclude about the state of motion of an object when velocity-time graph is a straight line making an angle with the time axis?
Uniformly accelerated
What does slope of position time graph represents?
It represents the velocity of the object.
What does a slope of a time graph represent?
The slope of a velocity-time graph represents acceleration.
What is the slope of constant velocity?
The Slope (which represents acceleration) of a constant velocity graph is Zero.
What does the slope of a speed-time graph represent?
The slope of a velocity-time graph represents acceleration.
What does slope of a speed time graph represent?
The slope of a velocity-time graph represents acceleration.
When velocity is changing what is happening to the slope on a position versus time graph?
That slope is the 'speed' of the motion. If the slope is changing, then the speed is changing. That's 'accelerated' motion. (It doesn't matter whether the speed is growing or shrinking. It's still 'accelerated' motion. 'Acceleration' does NOT mean 'speeding up'.)
Why is the distance time graph a straight line for?
A straight line on a distance - time graph represents a "constant velocity".
What best represents acceleration as presented on a graph?
Velocity change vs Time
What does a line slanting down from left to right represent on s velocity time graph?
A slanting line down from left to right represents an acceleration on the velocity time graph.
What is represented by a single point on a curved line in a distance time graph showing accelerated motion?
instantaneous acceleration* * * * *No it does not.The graph is a distance-time graph so the coordinates of a point on the graph represent the position (distance) at the specified time. The gradient of the tangent to the curve at that point represents the instantaneous radial velocity. The second derivative at that point, if it exists, would represent the acceleration.
