It says that in your molecule, the element in front of the little 2 occur twice. So in CO2, a carbon-atom occurs once, and the oxygen-atom occurs twice.
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"CO2" stands for carbon dioxide, which is a chemical compound made up of one carbon atom bonded to two oxygen atoms. The "2" in "2CO2" indicates that there are two molecules of carbon dioxide present.
The half reaction for the given chemical equation 2CO + O2 -> 2CO2 is: 2CO -> 2CO2 (in acidic medium) 2CO -> 2CO2 + 2H2O + 2e- (in basic medium)
There are 4 oxygen atoms in the formula 2CO2. Each CO2 molecule contains 2 oxygen atoms, so when you have 2 CO2 molecules, you get a total of 4 oxygen atoms.
C6H12O6+zymase+yeast---> 2 C2H5OH+2CO2+ENERGY
I believe the balanced chemical equation isC2H5OH+3O2 ---> 2CO2+3H2O the amount of energy relased from the equation is -1409kJ/molhowever I tried to calculate it out myself with a bond energy table i received from my professor and ended up with the number -1283kJ/mol...close enough
The balanced chemical equation for the combustion of ethanol is C2H5OH + 3O2 -> 2CO2 + 3H2O. Therefore, the stoichiometric coefficients are 1 for ethanol, 3 for oxygen, 2 for carbon dioxide, and 3 for water.
two carbon atoms and two oxygen atoms present
The balanced equation for the combustion of ethanol (C2H5OH) is: C2H5OH + 3O2 → 2CO2 + 3H2O
It is: C2H5OH+3O2 ----> 2CO2+3H2O
The balanced chemical equation for the burning of ethanol (C2H5OH) is: C2H5OH + 3O2 → 2CO2 + 3H2O.
2c2h5oh + 7o2 --> 2co2 + 3h2o