Since an alpha particle is a helium-4 nucleus, the resulting atom has an atomic mass that is 4 less, so 226 minus 4. Also, to get the element, look up the element number for radium, and subtract two from that.
4He or He4. 4 stands for the mass number of Helium Mass number = number of protons + number of neutrons Since the atomic number or number of protons in helium is 2, the number of neutrons in He-4 is also 2.
The proton proton chain consists of three chains:85.9 % PP1) H+H -> 2H -> 2H-(e+)-(v) + H -> 3He3He + 3He -> 4He + 2H14 % PP2) 3He + 4He -> 7Be -> 7Be-(e-)-(gamma) -> 7Li -> 7Li-(v)+H -> 4He + 4He0.1 % PP3) 7Be + H -> 8B - (gamma) -> 8Be + (e+) + (v) -> 4He + 4Hewhere i have used the notations:v for neutrino(gamma) for gamma particlee+ for positrone- for electronx% means it accounts for x% of the total conversion of H -> He
Actinium 225Ac--------alpha (4He) + 221Fr
The nuclear reaction is: 242Cm + 4He = 245Cf + n
251Cf --> 247Cm + 4He 247Cm --> 243Pu + 4He 243Pu --> 243Am + e- 243Am --> 239Np + 4He 239Np --> 239Pu + e- 239Pu --> 235U + 4He 235U --> 231Th + 4He 231Th --> 231Pa + e- 231Pa --> 227Ac + 4He 227Ac --> 223Fr + 4He, 227Th + e- 223Fr --> 219At + 4He, 223Ra + e- 227Th --> 223Ra + 4He 219At --> 215Bi + 4He, 219Rn + e- 223Ra --> 219Rn + 4He 215Bi --> 215Po + e- 219Rn --> 215Po + 4He 215Po --> 211Pb + 4He 211Pb --> 211Bi + e- 211Bi --> 207Tl + 4He, 211Po + e- 207Tl --> 207Pb + e- 211Po --> 207Pb + 4He 207Pb: stable
Since an alpha particle is a helium-4 nucleus, the resulting atom has an atomic mass that is 4 less, so 226 minus 4. Also, to get the element, look up the element number for radium, and subtract two from that.
213Bi --> 209Tl + 4He, 213Po + e- 209Tl --> 209Pb + e- 213Po --> 209Pb + 4He 209Pb --> 209Bi + e- 209Bi --> 205Tl + 4He 205Tl, stable
232Th --> 228Ra + 4He 228Ra --> 228Ac + e- 228Ac --> 228Th + e- 228Th --> 224Ra + 4He 224Ra --> 220Rn + 4He 220Rn --> 216Po + 4He 216Po --> 212Pb + 4He 212Pb --> 212Bi + e- 212Bi --> 208Tl + 4He, 212Po + e- 208Tl --> 208Pb + e- 212Po --> 208Pb + 4He 208Pb, stable Other isotopes of Thorium undergo beta decay, but they are not naturally occurring.
2 protons and 2 neutron
3He, 4He, 5He, 6He, 7He, 8He, 9He, 10He are the known isotopes of helium whereas the most stable ones are 3He, 4He
6Li + 1n --> 7Li --> 3H + 4He Hyrogen-3 or tritium
The equation for the beta decay of 87Kr is: 3687Kr --> 3787Rb + -10e where -10e represents a negative beta particle or electron.
4He or He4. 4 stands for the mass number of Helium Mass number = number of protons + number of neutrons Since the atomic number or number of protons in helium is 2, the number of neutrons in He-4 is also 2.
You could represent it as 4/8.
The proton proton chain consists of three chains:85.9 % PP1) H+H -> 2H -> 2H-(e+)-(v) + H -> 3He3He + 3He -> 4He + 2H14 % PP2) 3He + 4He -> 7Be -> 7Be-(e-)-(gamma) -> 7Li -> 7Li-(v)+H -> 4He + 4He0.1 % PP3) 7Be + H -> 8B - (gamma) -> 8Be + (e+) + (v) -> 4He + 4Hewhere i have used the notations:v for neutrino(gamma) for gamma particlee+ for positrone- for electronx% means it accounts for x% of the total conversion of H -> He
Actinium 225Ac--------alpha (4He) + 221Fr