For any n-sided plane figure the interior angles total 2n - 4 right angles.
A polygon with 50 sides, given the sum of all the interior angles in 8640.
360 degrees. All four-edged polygons (including parrallelogramz) have the equal interior sum of 360 degrees.
The sum of the exterior angles of all polygons equals to 360⁰.Since only the sum of the interior angles of all quadrilaterals equals to 360⁰, the polygon must have 4 sides.
Yes, the sum of the interior angles of any polygon is always equal to (n-2) * 180 degrees, where n is the number of sides.
180*2
No way. All polygons have the same sum of exterior angles.You need the sum of interior angles.
180 degrees, for all 3-sided polygons and triangles
octagon
The sum of all (interior) angles must equal 360 degrees
no ,is different .
All polygons have an interior angle sum of 180(n-2) degrees where n is the number of sides. 180(9-2)=180*7=1260 degrees
42