it means initial upwards height times time in seconds
42-It is not 42, idk what that is, it's -16t^2+vt+s, now that is the RIGHT answer!
H= -1/2gt2+vt+s Where H is the ending height g is the rate of gravity (32 ft/sec2 or 9.8 m/sec2) t is the time v is the initial velocity and s is the starting height.
Positive velocity: p=vt (position = velocity*time) Example: Write the position equation for a person who starts 3 meters behind the reference point and walks with a constant velocity v=6 m/s in the positive direction. Answer: p=-3+6t Example: What is the position of the person 5 seconds after the start of motion? Answer: p=-3+(6x5)=27 m. Negative velocity: p=p(0)+vt p(0) represents the position at time "0" which is also known as the y-intercept or the point where the line crosses the vertical axis. The velocity of the object in motion would be negative.
vt-v2
However you like. For some things distance does not vary at all - or not measurably so eg between London and New York. For objects under simple harmonic motion (such as a pendulum) the distance increases and decreases (according to quite a simple formula). For the archetypal drunken walk (or Brownian motion) the distance is random.
formula: h=-16t^2+vt+s H= final height T= time V= velocity S= starting height
42-It is not 42, idk what that is, it's -16t^2+vt+s, now that is the RIGHT answer!
This is the vertical motion model, used when solving for height that an object is dropped from, what height an object is at after so many seconds, what rate the object is falling at, and how many seconds have passed after dropping an object when it is at x height etc. etc. Most often used in Algebra 1 and 2.
cosine @-= t / vt
vg=vt +(ia *ra)
on the news and I think U MEAN TV NOT VT
H= -1/2gt2+vt+s Where H is the ending height g is the rate of gravity (32 ft/sec2 or 9.8 m/sec2) t is the time v is the initial velocity and s is the starting height.
Positive velocity: p=vt (position = velocity*time) Example: Write the position equation for a person who starts 3 meters behind the reference point and walks with a constant velocity v=6 m/s in the positive direction. Answer: p=-3+6t Example: What is the position of the person 5 seconds after the start of motion? Answer: p=-3+(6x5)=27 m. Negative velocity: p=p(0)+vt p(0) represents the position at time "0" which is also known as the y-intercept or the point where the line crosses the vertical axis. The velocity of the object in motion would be negative.
E=Vt + Ia jXS Where E excitation voltage Vt Terminal voltage Stator Current Ia Xs synchronous Reactance
s = at^2/2 = vt/2 = v^2/(2a)
vt-v2
Kd = (Ve - Vo)/(Vt - Vo) Ve = elution volume Vo = void volume Vt = volume total