42-It is not 42, idk what that is, it's -16t^2+vt+s, now that is the RIGHT answer!
H= -1/2gt2+vt+s Where H is the ending height g is the rate of gravity (32 ft/sec2 or 9.8 m/sec2) t is the time v is the initial velocity and s is the starting height.
Positive velocity: p=vt (position = velocity*time) Example: Write the position equation for a person who starts 3 meters behind the reference point and walks with a constant velocity v=6 m/s in the positive direction. Answer: p=-3+6t Example: What is the position of the person 5 seconds after the start of motion? Answer: p=-3+(6x5)=27 m. Negative velocity: p=p(0)+vt p(0) represents the position at time "0" which is also known as the y-intercept or the point where the line crosses the vertical axis. The velocity of the object in motion would be negative.
vt-v2
GARCH processes are used to model the conditional volatility of financial returns in discrete time. There are many many different types of GARCH, the most popular and simplest being the GARCH(1,1), where returns have mean mu and conditional variance vt (t indexes time): returnt = mu + sqrt(vt)et where et is a standardized innovation.Conditional variance follows a first order autoregressive process: vt= a + b* vt-1 + c* vt-1*et-1^2
formula: h=-16t^2+vt+s H= final height T= time V= velocity S= starting height
42-It is not 42, idk what that is, it's -16t^2+vt+s, now that is the RIGHT answer!
To calculate vertical thickness, you can use the formula: Vertical thickness = True thickness / cos(strike angle) To calculate true thickness, use the formula: True thickness = Vertical thickness * cos(strike angle)
The expression h = 16t^2 + vt + s represents a common physics equation for the height of an object in free fall where h is height, t is time, v is initial velocity, and s is initial height. The equation is derived from the kinematic equation s = ut + (1/2)at^2 with u = initial velocity = v and a = acceleration due to gravity = -9.81 m/s^2.
vg=vt +(ia *ra)
on the news and I think U MEAN TV NOT VT
H= -1/2gt2+vt+s Where H is the ending height g is the rate of gravity (32 ft/sec2 or 9.8 m/sec2) t is the time v is the initial velocity and s is the starting height.
E=Vt + Ia jXS Where E excitation voltage Vt Terminal voltage Stator Current Ia Xs synchronous Reactance
Positive velocity: p=vt (position = velocity*time) Example: Write the position equation for a person who starts 3 meters behind the reference point and walks with a constant velocity v=6 m/s in the positive direction. Answer: p=-3+6t Example: What is the position of the person 5 seconds after the start of motion? Answer: p=-3+(6x5)=27 m. Negative velocity: p=p(0)+vt p(0) represents the position at time "0" which is also known as the y-intercept or the point where the line crosses the vertical axis. The velocity of the object in motion would be negative.
vt-v2
Ventricular tachycardiaventricular tachycardia
The formula you are looking for is Vt = V1 + V2.