Add all the sums, then divide by the number of sums. (ie. the average.)
Can you please claify if you mean x=y^2/ pi*cos(x) , or x=y^2/cos(pi), since they are very different sums.
The pairs of positive integer factors of 80 are: 1 x 80 = 80 2 x 40 = 80 4 x 20 = 80 5 x 16 = 80 8 x 10 = 80 Since multiplication sums are commutative, the reverses of the sums also hold true. For example, such that 8 x 10 = 80, also 10 x 8 = 80, and so on.
1/x+a+b =1/x+1/a+1/b ---- ---- ---- ----
If you mean 27.905 added 3 times then it is 83.715
The positive integer factors of 3246 are: 1, 2, 3, 6, 541, 1082, 1623, 3246 Limiting the combinations of sums merely to multiplication sums using positive integer factors, the following sums can be made: 1 x 3246 = 3246 2 x 1623 = 3246 3 x 1082 = 3246 6 x 541 = 3246
The average or arithmetic mean.
Well, 1 is equal to 1. 9 is equal to 9. So any number from 0 to 9. I do not think this is what is meant by the question. If you mean any number with more than one digit. There is no such number. Because 11 sums to 2. 19 sums to 10. 21 sums to 3. 29 sums to 11. 111 sums 3. 119 sums to 11. The sums do not grow as fast the increase of digits.
5 x 8
Applying the rules of BODMAS, whereby multiplication sums are carried about before addition sums, 26 + (2 x 3) = 26 + 6 = 32.
It might have been possible if you explained what you mean by "like that".
For an array of numbers, it is the square of the sums divided by the sum of the squares.