It will decrease the voltage drop.
If the load resistance is decreased, the ripple voltage in a power supply circuit typically increases. This occurs because a lower load resistance draws more current, leading to a greater voltage drop across the output capacitor as it discharges more quickly between charging cycles. Consequently, the capacitor may not have enough time to fully charge during each cycle, resulting in a higher ripple voltage. Therefore, a decrease in load resistance generally results in increased ripple voltage.
No.
As the resistance in the wire increases due to the longer length the voltage drop across the wire resistance increases. This leaves less voltage across the load. To overcome this voltage drop usually a larger size wire which has less resistance is used. A safe nominal figure for voltage drop is to keep it at 3% of the line voltage.
By Ohm's Law, current is voltage divided by resistance, so if you double both the voltage and the resistance, the current would remain the same.
The AC skin effect causes the flow of alternating current to concentrate near the surface of a conductor, reducing its effective cross-sectional area for current flow. This increases resistance and can lead to power loss and decreased efficiency in electrical conductors.
Ohm's Law says that Voltage = Current x Resistance (Load). Therefore Current = Voltage / Resistance and as resistance decreases current increases and as resistance increases current decreases.
Supply voltage , temperature , frequency are factors that effect the electrical parameters of opamp
The electrical potential energy increases as the voltage is increased. It further excites the filament in the bulb more than a lessor voltage would. Using good old ohm's law (Voltage = Current x Resistance), a larger voltage applied to a bulb at the same resistance increases the current proportionally and larger currents has the effect to cause higher temps in conductors
There are two ways of looking at this question, depending on what you mean by 'voltage'.The first applies to the supply voltage, which is quite independent of a circuit's load resistance. In other words, changing the load resistance will have no effect on the supply voltage (within limits; for example, and extremely-low resistance might cause the supply voltage to collapse!).The second applies to any voltage drops, which are proportional to the resistance across which they appear. If, for example, you have a high resistance and a low resistance, in series, then the higher voltage drop will appear across the higher resistance.
Yes.
I = V/R (I is inversely related to R) Therefore, if R is decreased, I will increase if V is held constant.
If you double the voltage in a circuit, the power is quadrupled, assuming the resistance stays the same.