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First use the cosine rule:

If the three sides are of lengths a, b and c and C is the angle opposite side c, then

CosC = (a2 + b2 - c2)/2ab

So angle C = Cos-1[ (a2 + b2 - c2)/2ab ]

Angles A and B can be found similarly, or more simply, using the Sine rule:

SinA/a = SinB/b = SinC/c

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Q: What equation do you use to find a triangles angle with 3 side lengths?
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