Points: (-3, -23) and (5, 9)
Slope: 4
Equation: y = 4x-11
Points: (0, 3) and (5, 23) Slope: 4 Equation: y = 4x+3
If you mean of points of (3, -4) and (5, 1) then the equation works out as 2y=5x-23
Points: (5, -2) and (4, 3)Slope: -5Equation: y = -5x+23
Points: (13, 17) and (19, 23) Midpoint: (16, 20) Slope of required equation: 5/4 Its equation: 4y = 5x or as y = 1.25x Its distance from (0, 0) to (16, 20) = 4 times sq rt 41
Slope=8 point=(-7,3)
If: y = -5x+3 then the points are (2, -7) and (6, -27)
first we set x=23(1/3) now set the equation equal to 0. x3=23 x3-23=0 now we can set our equation in the formula xn+1=xn-(xn3-23/3xn2)
Points: (-3, 1) and (5, 6) Slope: (1-6)/(-3-5) = 5/8 Equation: y-1 = 5/8(x--3) => 8y-8 = 5(x--3) => 8y = 5x+23 Equation: y-6 = 5/8(x-5) => 8y-48 = 5(x-5) => 8y = 5x+23
You'd need another equation to sub in
3e+23
Points of line: (13, 17) and (19, 23) Its slope: 1 Its equation: y = x+4 => y-x = 4 Multiply all terms by 4: 4y-4x = 16 Equation of: 4y = 5x => 4y-5x = 0 Subtacting equations: x = 16 By substitution point of intersection is at: (16, 20)
11 + 7 + 5 = 23