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4 = 2²

→ 4^x = 2^(2x)

We want 4^x > 40

Taking logs gives:

x log 4 > log 40

→ x > log 40 / log 4

This can be solved to find a value of x to be greater than (approx) 2.661

Thus 4^2.662 = 2^5324 ≈ 40.06 is an example.

So all powers of 4 where the power is greater than approx 2.661 with 2 to the power of twice that power of 4 will solve the problem.

If you are looking for integer powers of 2 and 4, then the first integer power of 4 is 4³ = 64 = 2^6, and the solutions are:

4^3 = 2^6 = 64

4^4 = 2^8 = 256

4^5 = 2^10 = 1024

etc.

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Q: What example is there for when a power of 2 is equal to a power of 4 and greater than the number 40?
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