A right triangle with sides in length of 3,4, and 5 has a hypotenuse of length 5. It's the best example because all the numbers are whole (integers) and its the smallest of its kind.
Hypotenuse is something that I have learned in math class.
base squared times height squared equals the hypotenuse squared. then you know the hypotenuse.
To find the hypotenuse of a right triangle in Python, you can use the Pythagorean theorem, which states that the square of the hypotenuse (c) is equal to the sum of the squares of the other two sides (a and b). You can calculate it using the math module. Here's a simple example: import math a = 3 b = 4 hypotenuse = math.sqrt(a**2 + b**2) print(hypotenuse) This will output 5.0, which is the hypotenuse of a triangle with sides of length 3 and 4.
Sin= Opposite/Hypotenuse Cos= Adjacent/Hypotenuse Tan= Opposite/Adjacent
opposite^2+adjacent^2=hypotenuse^2 ____________ X=/hypotenuse^2 One decimal place would be, for example. 22.7 cm
If you know the side lengths, then you can use sin(Θ) = (Opposite)/(Hypotenuse), so Θ = Sin-1(Opposite/Hypotenuse), for example. You could get close to the number of degrees in an angle with a protractor.
Dependent on what side you are given you would use Sin(Θ) = Opposite/Hypotenuse just rearrange the formula to Hypotenuse = Opposite/Sin(Θ). Or if you are given the adjacent side use Cosine(Θ)=Adjacent/Hypotenuse, then: Hypotenuse = Adjacent/Cosine(Θ)
That is it. Just the hypotenuse - provided you have the correct triangle.
I'm assuming Pythagorus - hence the Pythagorean Theorem of which you use to figure the length of the hypotenuse.
Use Pythagoras' theorem...a2 + b2 = c2where c is the length of the hypotenuse in a right-angled triangle.
Archimedes theorem says "the square of the hypotenuse is equal to sum of the squares of the other two sides" so in this example: hypotenuse2 = 62 + 62 = 72 hypotenuse = square root of 72 = 8.485 Alternately: Sin 45o = opposite/hypotenuse = 6/hypotenuse So hypotenuse = 6/sin 45 = 6/0.707 = 8.485
Depending on the information given;- If two other(shorter) sides are known, use Pythagoras. h^(2) = a^(2) + b^(2) If one angle and one side are given then you use Trigonometry . Sin(angle) = opposite/ hypotenuse hypotenuse = opposite/Sin(angle) or Cos(angle) = adjacent/hypotenuse hypotenuse = adjacent/ Cos(Angle).