The factors of 112 are 1, 2, 4, 7, 8, 14, 16, 28, 56, 112. None of them differ by 22.
As exponents: 22*112 = 484
the prime factors of sum of 121 is 112 and 22
The factors for 112 are 1,2,4,7,8,14,16,28,56, and 112
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The prime factors of 112 are: 2 and 7
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As a product of its prime factors: 2*2*11*11 = 484 or as 22*112 = 484
The factors of 112 are 1, 2, 4, 7, 8, 14, 16, 28, 56, 112.
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The (10) factors of 112 are: 1, 2, 4, 7, 8, 14, 16, 28, 56, 112
The HCF of 112 and 63 is 7
To find two factors that multiply to 112 and add up to 9, we can set up a system of equations. Let's denote the two factors as x and y. We have the following equations: xy = 112 and x + y = 9. By solving the system of equations, we can find that the factors are 8 and 14, as 8 * 14 = 112 and 8 + 14 = 22.