A lot of possibilities. A few ones: * (9-8) * (7-6) * (5-4) = 1 * 9 + 6 + 5 - 8 - 7 - 4 = 1 * 7*4 / (9+8+6+5) = 1 * 6*5 - 7*4 - 9 + 8 = 1 * etc., etc.
There are many. Her is one: 1 + 4 - 5 - 7 + 9 + 11 = 13
There are an infinite number of triangular numbers that are also squares. You can generate such numbers using the formula: Sn+1 = 4Sn(8Sn + 1) With the first Sn being 1. This gives the next such number as: Sn+1= 4 (8 + 1) = 36 You can then plug that into the equation to get: Sn+1 = 4 x 36 (8 x 36 + 1) = 41616 and so on.
two numbers multiplied together that gives you 20 are 10 and 2. also have 5*4, 1*20, 2.5*8 ect
big/small so if it was 1/4 2/8 divide to numbers across 8/4 and 2/1 i THINK
-4 and +4
-1
1 and 56, 2 and 28, 4 and 14, and 7 and 8.
There are 4 such integers: 25, 49, 73, 97
There is no formula, but I can point out that: between the numbers you get: +1,+2,+3,+4+5... so the next term would be +6 or 21
The next two can be anything you want them to be (as a formula can be found which matches the sequence so far and gives you any two numbers you want). However, the simplest formula is probably "the next term is the current term multiplied by 1.5" giving the next two as 20.25 and 30.375 The formula for the nth term is given by t(n) = 4×1.5^(n-1) for n = 1, 2, 3, ...
Rectangular numbers are of the form n(n+1) for n = 1, 2, 3, 4, 5, 6, ... The first few rectangular numbers are: 2, 6, 12, 20, 30, 42, ...
1 x 28, 2 x 14, 4 x 7