One and two
2
1 and 2.
The hcf is 14
1
1 and 2.
2 and 10 go into 40 and 50 evenly.
Two goes into 98 a total of 49 times. This is calculated by dividing 98 by 2, which equals 49. Therefore, 2 divides evenly into 98, with no remainder.
No, but 98 is evenly divisible by 1, 2, 7, 14, 49, 98.
1, 2, 7, 14, 49, 98, 343, 686, 2401, 4802.
1, 2, 5 and 10
1 2 7 14 49 and 98 all divide into 98 evenly.
28. If you divide 28 into 1,400 you get 1|50. 28 goes into 28 once.