One and two
2
1 and 2.
The hcf is 14
1
1 and 2.
2 and 10 go into 40 and 50 evenly.
The numbers that go into both 29 and 50 evenly are their common divisors. Since 29 is a prime number, its only divisors are 1 and 29. The divisors of 50 are 1, 2, 5, 10, 25, and 50. Therefore, the only number that goes into both 29 and 50 evenly is 1.
Two goes into 98 a total of 49 times. This is calculated by dividing 98 by 2, which equals 49. Therefore, 2 divides evenly into 98, with no remainder.
No, but 98 is evenly divisible by 1, 2, 7, 14, 49, 98.
1, 2, 7, 14, 49, 98, 343, 686, 2401, 4802.
1, 2, 5 and 10
1 2 7 14 49 and 98 all divide into 98 evenly.