Suppose "a" is the length of the side of a square.
Area of the square = axa = a2
Now if we double the sides then the length of each side will be "2a".
The area of the square with doubled side = "2ax2a" = 4a2 or 4 times the previous value.
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No, it will be quadrupled.
The area gets doubled.
If the altitude is not changed, the area would be doubled.
The area increases as the square of the radius (or diameter). So if you double the radius you * 4 (quadruple) the area. Treble the radius, you *9 the area.
If the linear dimensions are doubled, the area is multiplied by (2)2 = 4 .
four times the initial value
No, it will be quadrupled.
the new area will be fourfold, not doubled. try it on squared paper and see how the shape increases from one square into four...
When the diameter is doubled, perhaps? Then the area is 4 x larger.
The area gets doubled.
If the altitude is not changed, the area would be doubled.
The area increases as the square of the radius (or diameter). So if you double the radius you * 4 (quadruple) the area. Treble the radius, you *9 the area.
Area = length*width new Area = 2 * length * width Area is doubled
Force is not dependent upon area.
Refer to the question. It says the base is doubled! And when the dimensions of the base are doubled, the area is multiplied by 4.
If the linear dimensions are doubled, the area is multiplied by (2)2 = 4 .
It quadruples.