Q: What happens to the digits 2 and 4 when finding the product?

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The 2-digit number must be 20, because it is the only 2-digit number whose sum of its two even digits, 2 + 0 = 2, is greater than the product of its two even digits, 2 x 0 = 0. Moreover, 20 is a product of the two consecutive integers 4 and 5.

There are seven digits: 8,000,000

231

225 = (15)2 2*2*5=20 3 digits in 225

81

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You could be 22? 2 + 2 = 4 2 x 2 = 4

The 2-digit number must be 20, because it is the only 2-digit number whose sum of its two even digits, 2 + 0 = 2, is greater than the product of its two even digits, 2 x 0 = 0. Moreover, 20 is a product of the two consecutive integers 4 and 5.

If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.

36 is twice the product of its digits multiplied. 3 times 6 equals 18, and 18 times 2 equals 36.

from 3 digits (10x10) to 4 digits (99X99)

19

There are seven digits: 8,000,000

231

2 digits because 1.88*71 = 133.48

225 = (15)2 2*2*5=20 3 digits in 225

20

81