An octagon based pyramid, perhaps.
A triangle with side a: 8, side b: 8, and side c: 8 cm has an area of 27.71 cm2
A quadrilateral bipyramid is one possible answer. This is two pyramids with the same quadrilateral base - one on each side of the "base".
root square of 73
hypotenuse= 16.24
8 inches.
= 1/2 × Perimeter × [Side Length] + [Base Area] = 0.5*(3*8)*4*sqrt(10)+0.5*8*4tan60o = 158.72 (base area is 0.5*base length*perp ht, per ht is just 0.5*side*tan60o as triangel is equilateral) alex
The base of a cube is a square, so the area of the base of the cube is the area of that square. The area of a square is s2, where s is the length of on side. Side all edges of a cube have the same length, it doesn't matter which edge you use. Example: Find the area of the base of a cube with edges of length 7: A = 72 = 49 Example: Find the area of the base of a cube with volume 8 cubic meters. The volume of a cube is equal to s3, where s is the length of a side. 23=8, so 2 is the length of a side, and the area of the base is 22 = 4.
Such a pyramid cannot exist. If it is a regular pyramid with side length 8, its slant height MUST be less than 8. In fact, it is approx 6.39.
462 base 8 - 177 base 8 = 263 base 8 , (that's 179 in base 10) I used the octal feature on the windows calculator.
503 base 10 = 767 base 8 503 base 8 = 323 base 10
Okay. A square pyramid has 5 faces. So a pyramid with twice that would have 10 faces. You subtract 1 for the base and you get nine. Therefore you have 9 sides. Divide 72 by 9 and you get 8. So one side is 8 ft.
If you want it to remain a square then the base is multiplied by 8 also and the area is multiplied by 64. If not, and you multiply the sides only, it is multiplied by 8. If you multiply only one side, then the area is multiplied by 4.5