A square or other rhombus (= parallelogram with 4 equal sides, whether or not they're at right angles).
Also, any other regular 4n-gon -- i.e., regular polygon whose number of sides is a multiple of 4 -- will have pairs of perpendicular diagonals. So a regular octagon has two such pairs.
The diagonals of a rectangle are never perpendicular but the diagonals of a square are perpendicular
The diagonals of a square are always perpendicular.
Yes, the diagonals of a rhombus are perpendicular.
A rhombus has 4 equal sides and the diagonals are always perpendicular
No. The diagonals of a rhombus are perpendicular only if the rhombus is a square.
No but the diagonals of a square, rhombus and a kite are perpendicular to each other
No but its diagonals are perpendicular
The diagonals of a rhombus are perpendicular
Yes the perpendicular diagonals intersect at right angles or 90 degrees
No, not necessarily. It would have to also be a square or a kite in order to have perpendicular diagonals.
The diagonals of a square are perpendicular whereas the diagonals of a rectangle are not perpendicular.
Sure, a square is a rectangle and the diagonals of a square are perpendicular.