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How many square foot equals 250m²?
Answer = 2690.9776 ft21 ft = .3048 m1 ft2 = .0929 m21 m2 = 10.7639 ft2250 m2 = 2690.9776 ft2
How do you find final velocity given mass of both objects and there initial velocities and one of their final velocities?
Suppose the two masses are m1 and m2. Their initial velocities are u1 and u2 and final velocities are v1 and v2. Then, using conservation of momentum. m1*u1 + m2*u2 = m1*v1 + m2*v2 Both m1 and m2 are given. Their initial velocities u1 and u2 are given and one of the two final velocities v1 and v2 is given which leaves only one unknown. So substitute all those values and calculate away.
What does the slope on a force vs mass graph represent?
Let us suppose we are plotting y vs x and obtain a straight line. Then we pick a set of two coordinates, x1,y1 and x2,y2 The slope, M, is then given by the equation M (y2-y1)/(x2-x1) If we apply this to a force vs mass graph, we obtain the expression M (F2-F1)/(m2-m1),but F ma according to Newton's second law, where a is the acceleration, which leads to (m2a2-m1a1)/(m2-m1), but if a2 a1 a, as it will if the line is straight, then M a(m2-m1)/(m2-m1) a, so the slope, M, of your graph is acceleration.
What are the Conditions for parallelism and perpendicularity of linear functions?
Condition of Parallelism: The Slope of two (lines) linear functions must be equal. i.e. m1=m2 Condition of perpendicularity : The product of slope of two (lines) linear functions must be equal to - 1. i.e. m1.m2=-1
What value or values of m1 are allowable for an orbital with i equals 2?
2
If the m1 equals SA and m3 equals 23 what is the m?
if(m1>m2) f=m1; s=(m2>m3)?m1!m3 what its meaning of this?
What is the difference between M1 and M2?
What is the difference between M1 and M2?
What represents the correct relationship between the slopes of perpendicular lines?
If the slopes are m1 and m2 then m1*m2 = -1 or m2 = -1/m1.
Is currency held within banks part of m1 or m2?
Cash is part of M1.
What happens to the gravitational force when the distance between the 2 objects is trippled?
The force, written as an equation, is:F = G (m1)(m2) / r2, whereF is the Force between the massesG is the gravitational constant (~= 6.674 x 10-11 N m2/kg2)m1 is one of the massesm2 is the other massr is the distance between the masses (center to center)Take the formula, and solve for r (I'll show the steps): Fold = G (m1)(m2) / r2.(r2)(Fold)= G (m1)(m2)(r2)= G (m1)(m2) / (Fold)r= √ [ G (m1)(m2) / (Fold) ]Plug the formula into itself, but remember, r = 3r (it tripled).Fnew= G (m1)(m2) / (3r)2.Fnew= G (m1)(m2) /(3√ [ G (m1)(m2) / (Fold) ])2.Fnew=G (m1)(m2)/(32G (m1)(m2) / (Fold) )
How do you write c code for ternary search?
this procedure work for ternary search int tsearch(int *a,int i,int j,int k) { int m1,m2,len; len = j - i + 1 ; m1=i + (int)floor((float)(len))/3; m2=i + (int)ceil((float)(len))/3; if(k==a[m1]) { printf("\nno found at %d",m1); return m1; } else if(k==a[m2]) { printf("\nno found at %d",m2); return m2; } if(len!= 0) { if(k<a[m1]) return(tsearch(a,i,m1-1,k)); if(k>a[m2]) return(tsearch(a,m2+1,j,k)); } else return -1 ; }
Two billiard balls of equal mass undergo a perfectly elastic head collision. What will be their speeds after the collision.?
The velocities of the two bodies after the elastic collisions are given by V1=(M1-M2)U1/(M1+M2)+2M2U2/(M1+M2) V2=(M2-M1)U2/(M1+M2)+2U1M1/(M1+M2) Where, V1,V2 are the velocities of the two bodies after collision. U1,U2 are the velocities of the two bodies before colision.(U1>U2) M1,M2 are the masses of the two bodies. when the mass of two bodies are equal that is M1= M2 then V1=0+2MU2/2M=U2 V2=0+2MU1/2M=U1 Thus when two billiard balls of equal masses undergo perfectly elastic collision the velocities the two bodies are interchanged after the collision.
Why are m3 and m2 higher than m1?
because 3>2>1 ? Other than that, depends on what m1,m2 and m3 represent.
Factors that affect gravity between objects?
The force of gravity is F=G*m1*m2/r^2 G is the universal gravitation constant 6.67*10^-11 m^3kg^-1s^-2 m1, m2 are the masses of the two objects, r is the separation. The force on m1 acts in the direction of m2, and the force on m2 acts in the direction of m1.
Two objects attract each other gravitationally with a force of 2.5x10-10 N when they are 25m apart Their total mass is 4.0kg find their individual masses?
Alright, so basically you're given: m1+m2=4.0kg, r=25m, Fg=2.5*10-10N We know that Fg=Gm1m2/r2 Using the fact that m1+m2=4.0kg, we know that m2=4.0kg-m1 So: Fg=Gm1(4.0kg-m1)/r2 =G(m1(4.0)-m12)/r2 So: (-G/r2)m12+(4G/r2)m1-Fg=0 Here we can use the quadratic formula to solve for m1 Once you have m1, just use m1+m2=4.0kg to find m2 I'll leave the actual number crunching to you. Hope this helps!
What is the difference between the M1 and M2 money supply?
M1 is what is outside the banking system: Your cash, coins, your checking account. M2 is: All of M1 plus, savings accounts, money in banks, small time deposits...etc .
What is the difference between a m1 carbine and a m2 carbine?
M1 carbines are semi-automatic and M2s are full automatic.
