Always true. To see this draw the circle which passes through the three points of the triangle. Reproduce the reflection of the triangle on the hypotenuse (which passes through the centre). Then use the theorem of intersecting chords of a circle to give the result immediately. It's also simply proved by algebra.
The altitude of a right triangle if the base is 96 and the hypotenuse is 240 is: 229.87
By using Pythagoras' theorem: hypotenuse^2 minus base^2 = altitude^2
Sqrt x2+y2
Triangle
Triangle
What a neat little problem ! I'll remember this one, and I'll use it. The altitude to the hypotenuse is 12.0 millimeters long.
The altitude of a right triangle if the base is 96 and the hypotenuse is 240 is: 229.87
It is: c2-b2 = a2 whereas c is the hypotenuse, b is the base and a is the altitude
By using Pythagoras' theorem: hypotenuse^2 minus base^2 = altitude^2
Sqrt x2+y2
A Triangle
A triangle.
Triangle
Triangle
The altitude of a triangle IS a geometric concept so it intersects geometry in its very existence.
True, because the slant height and the altitude, or height, of the pyramid form one leg and the hypotenuse of a triangle withing the pyramid, and the hypotenuse of a triangle is always the longest side- it is not possible for the hypotenuse to be equal to the legs of a right triangle. (It is a right triangle because an altitude is perpendicular to the base of a pyramid.)
A geometric figure that has three line segments for sides is a triangle. Rectangles and squares are made of four line segments, while a circle is made out of a pair of arcs.