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What if your truck weighs 3500 kg you drive up a gentle slope that is 5kg long At the top of the slope you are 200m higher in elevation then when you started with no friction what was the force?
Wiki User
∙ 13y ago
14000N is the correct answer
Wiki User
∙ 13y ago
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A truck 3500kg if drive up a slope that is 0.5km at the top of the slope your 200m higher in elevation what is the force has your engine exerted to drove up the slope?
14000N
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What if your truck weighs 3'500kg you drive gentle slope is 05km long at the top slope you are 200m higher in elevation when you started assuming no friction what force you engine drove up?
1400N
A light truck weighs 3500kg you drive up a gentle slope 0.5km long at the top ofslope you are 200 m higher in elevation than when you stated assuming no friction what force has your engine exerted to?
14000N
What if your light truck weighs 3500 kg you drive up a gentel slope that is 0.5 km long at the top of the slope you are 200 m higher in elevation than when you started assuming no friction what force?
The answer is 14000N. 3500(9.8)/(500/200) = 1400(9.8) = 13720 A 44% grade is not a "gentle slope."
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A truck weighs 3500kg you drive 0.5 km long The top of the slope you are 200 m higher in elevation than when started Assuming no friction what force has your engine exerted to drive up this slope?
7000N isn't the correct answer i think its 14000n. oplease help me figure this out
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