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Q: What is 'y to the second power plus x to the second power equals 5 to the second power' solved for x in terms of y?

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The problem cannot be solved because there is no equation (or inequality) in the question: only three disjoint terms.

2a to the second power. If you combine the like terms, (a to the second power + a to the second power), it would be the same as 2a to the second power.

second or third

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To solve for y in terms of x, divide both sides of the equation by 2: y = x/2.If x=2y then you have already solved for x.

A joule / second is a watt. The watt is a unit of power. In general terms, power means energy expended, produced, or transferred, per time unit.A joule / second is a watt. The watt is a unit of power. In general terms, power means energy expended, produced, or transferred, per time unit.A joule / second is a watt. The watt is a unit of power. In general terms, power means energy expended, produced, or transferred, per time unit.A joule / second is a watt. The watt is a unit of power. In general terms, power means energy expended, produced, or transferred, per time unit.

One linear equation in two variables cannot be solved. You can only express one of the variables in terms of the other.

In classical times, the second power was described in terms of the area of a square. This led to the use of the term squareto mean raising to the second power.

For the expressions: 2d 5d2 4x2 d2 6x The like terms wold be 5d2 and d2 If you were to add all of those terms together, they would be: 6d2 + 4x2 + 2d + 6x

Power is the rate of doing work ... the amount of work done every second.1 watt of power = 1 joule of work every second

It is a fifth order polynomial. The two terms cannot be combined, except to factor out x² and get x²(x³ + 1). This can be solved for 5 roots: 0, 0, -1, and two complex roots: 1/2 ± i(√3)/2

The three terms are 3x2, 7x and 1

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