2(5c + 2d)(5c + 2d)
4c2 + 5c + 2c = 4c2 + 7c = c(4c + 7)
c2 + 5c + 6 = (c + 2)*(c + 3)
15 ac + 20 bc + 6 ad + 8 bd =3a (5c + 2d) + 4b (5c + 2d) =(3a + 4b) (5c + 2d)
The like terms are sums of b terms and c terms separately 5c+2c+3c+4b 5c +2c + 4b + 3c => 10c + 4b
12c + 2b
It IS expanded.
Group 5c-2c and 7d-3d and it comes to 3c+4d
Collect like terms: 11c+6d-5c-8d = 6c-2d
31° C = 87.8 °F The formula is F = 9/5C + 32 Fahrenheit equals 9/5 times the Celsius temperature, plus 32 degrees.
That is 27 x 9 = 243
The answer is 252, Exept, you added a "p" at the end. Is this just a misspelling, or does it mean something?
5c + 15= 30 - 15 -15 5c = 15 If your solving for just c..... 5c/5 = 30/5 c= 3 Hope this helps adding further your question is incomplete you must ask for the value of C, since its a arithmetic equation.
4c/15+5c/6 8c/30+25c/30 33c/30
5c+7=23 -7 -7 5c=16 /5 /5 c= 3 & 1/5 or 16/5 thats really easy algebra 1 homework isn't it
127 easy math people
The correct answer is of course -40 degrees.Whilst the equations are both linear, if you were to plot them both on the same graph, you would see that the results do intersect (at -40degrees). Another, slightly more geeky, way to get the answer is to use the 2 equations1. F=9/5C +32 ... used to convert from centigrade (Celsius) to Fahrenheit2. C= 5/9(F- 32).... used to convert from Fahrenheit to Centigrade (Celsius)Firstly write the write the equations so that they are equal (C=F), and then we can solve the simultaneous equations. So it looks like this:9/5C+32 = 5/9(F-32). (this is when Fahrenheit and Celsius/ Centigrade are equal)Then you solve for either F or C, by substituting for either F or C into the equation above (1. if you are solving for F, or 2. if you are solving for C) lets use number 1 and solve for FIt now looks like this:9/5C+32 = 5/9((9/5C+32)-32) (I just put in (9/5C + 32), where F used to be.To solve it we just use some simple rules of equations to try to get C on its ownFirstly divide both sides by 5/9) and it look like this:9(9/5C+32)/5 = ((9/5C+32)-32)Then simplify right hand side by removing the brackets like this:9(9/5C+32)/5 = 9/5C [of course 32-32=0]Next simplify the left hand side by opening brackets (it is done by multiplying everything inside the brackets by 9):(81/5C+288)/5 = 9/5CTo get rid of 5 on bottom of left hand side, you muliply both sides by 5 and get:(81/5C+288) = 45/5CNext remove the brackets arent needed (nothing to do outside the brackets):81/5C+288 = 45/5CNext move Cs together and numbers to other side (by taking 288 from both sides and taking 45/5C from both sides), and it looks like this:81/5C-45/5C =-288Now solve the left hand side (easy as they are both over 5C), so its just 81-45:36/5C=-288Next multiply both sides by 5 (gets rid of the 5 on the bottom of left hand side) and you get:36C=-1440Now we divide both sides by 36 (makes C= to 1), and we get:C=-1440/36Now whack that into a calculator and Hey Presto:C=-40(it also work if you substitute for C)So the temperature at which Celsius = Fahrenheit is -40 degrees(I hope this helped)Use this equation to convert degrees Celsius/Centigrade (ºC) to degrees Fahrenheit (ºF): [°F] = [°C] × 1.8 + 32
= 90 (9*10)
(5c - 2)(c +1)