The like terms are sums of b terms and c terms separately
5c+2c+3c+4b
5c +2c + 4b + 3c => 10c + 4b
4a + 3c - 2b - c + a - b = 5a - 3b + 2c
a + 7b + 2c
4c+2 = 3c+9 4c-3c = 9-2 c = 7
3c-d
3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4
4 + 3c = 2c + 2Subtract 4 from each side:3c = 2c - 2Subtract 2c from each side:c = -2
6c.
-((3c - 4)(3c + 4)(2c - 5)(2c + 5))
2c + 4 - 3c = -9 + c + 5 -c + 4 = c - 4 -2c = -8 2c = 8 c = 4
4a + 3c - 2b - c + a - b = 5a - 3b + 2c
a + 7b + 2c
2c+4c-3c+5c = 6c +2c = 8c
c-2b
2c-10
Group 5c-2c and 7d-3d and it comes to 3c+4d
ok, let's see: (3a-2a) + (2b+5b) +(-c +3c) = a + 7b +2c I think that's right.
To simplify the expression (3c - 7 + 2c - 5), first combine like terms. The (c) terms (3c) and (2c) add up to (5c), while the constant terms (-7) and (-5) combine to (-12). Therefore, the simplified expression is (5c - 12).