If: |x|-3-6 = 2
Then: |x| = 2+3+6 = 11
If x > 0, then x = 11
If x < 0, then x = -11
6 + 2K = 11 subtract 6 from each side - 6 + 6 + 2K = 11 - 6 2K = 5 divide the integers both sides by 2 K = 5/2 check 6 + 2(5/2) = 11 6 + 10/2 = 11 6 + 5 = 11 11 = 11 checks
2*(6/6 + 11) = 2*(1 + 11) = 2*12 = 24. Simple!
The union of sets A and B is {2, 3, 6, 11, 16}
2 6/11
Multiplication is simply repetitive addition. For instance, the expanded form of 2 * 3 is: 2 + 2 + 2, or 3 + 3. The expanded form of 5 * 6 is: 5 + 5 + 5 + 5 + 5 + 5, or 6 + 6 + 6 + 6 + 6. From the information above, it is evident that 11 * 5 = 11 + 11 + 11 + 11 + 11, and 11 * 6 = (11 * 5) + 11 So, substitute 55 for 11 * 5: 11 * 6 = 55 + 11 11 * 6 = 66
2/3 x 2/2 = 4/6 7/6 + 4/6 = 11/6 11 = 6 + 5 Answer: 11/6 or 1 and 5/6
1/2 x + 6 = 11 1/2 x + 6 - 6 = 11 - 6 1/2 x = 5 2*(1/2 x) = 5*2 x = 10 1/2 of 10 is 5, 5 plus 6 is 11 QED
6/11
2*3=6 11-6=5 so the answer is 5
1, -1, 11, -11 1, 2, 3, 6
-15
2x3x11 66/11=6 6/3=2 2/2=1