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If you mean: -x+3y = 6 and x+3y = 18 then by substitution x = 6 and y = 4
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∙ 9y ago
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How do you solve 2x-3y6?
just solve for x. 1) add 3y6 to both sides 2x=3y6 2) divide both sides by 2 to get x by itself: x=3y6/2
How many ordered pairs are in 15x plus 3y6 and 2y-10x plus 4?
There are infinitely many in each of the two curves/lines.
What model is this Yamaha with VIN 3Y6-101457?
SR-250
What model is this Yamaha with VIN number 3Y6-101457?
SR250 pre 1981
How do you write the equation -x 3y6 in slope-intercept form?
you mean -x + 3y + 6 = 0? y = x/3 - 2
Graph 2x 3y6 on a plane?
I'm sorry I cant graph this, because I don't have a way to show you. But, you can look on google.com, and type in 'graphing calculator'. This should help you.
What is the simplified radical form of square root of 45y12?
sqrt(45y12) = sqrt(5*9y12) = sqrt(5)*sqrt(9y12) = sqrt(5)*3y6
What is the area of the triangle formed by the 2x 3y6 and the coordinate axes?
If you mean: 2x+3y = 6 then the coordinates are (3, 0) and (0, 2) giving the triangle an area of 3 square units
Which statement is true about the graphs of these equations 2x-3y6 4x-6y1?
If you mean: 2x-3y = 6 and 4x-6y = 1 then it works out that the equations are parallel to each other because both of their slopes are 2/3
Can you add unknowns that have coefficients and exponents?
the unknowns must be the same variable and the exponents have to be the same. examples) x4 + y4 cannot be added because they are not the same variable. x3 + x2 cannot be added because they have different exponents. 3y6 + 5y6 can be added because they have the same variable and exponents. (answer: 8y6)
What is the slope of 5x 3y6?
This question is missing crucial information. Specifically the mathematical operators... as in +, -, x, /,=... and so on. POSSIBLE INTERPRETATIONS OF QUESTION: 5x-3y=6 ---> SLOPE= 5/3 5x+3y=6 ---> SLOPE= -5/3 5x*3y=6 ---> SLOPE= Not Applicable (Rational Function) 5x/3y=6 ---> SLOPE= 5/18 5x=3y-6 ---> SLOPE= 5/3 5x=3y+6 ---> SLOPE= 5/3 5x=3y*6 ---> SLOPE= 5/18 5x=3y/6 ---> SLOPE= 10/1 I hope one of these worked.
