11
4+4=8+0=8+1=9+1=10+0=10+1=11 It equals 11. You're welcome.
x2+12x+11=0 (x+11)(x+1)=0 x=-11 or x=-1
(-5)+(-8)+(-13)+(-16)+(-8)+11+0 11-16-13-8-8-5 -5-13-16-5 -18-21 -39
(11, 1, 0) and (0, 1, 11) are the two possible solutions.
It is: 3x2+6x-11 = 0
x=4 x=0
0 plus 0 plus 0, repeated multiple times, equals 0. Adding zero to zero does not change the value, so regardless of how many times you add it, the sum remains 0. Therefore, the final result is simply 0.
The expression can be simplified by following the order of operations. First, calculate the multiplication: (1 \times 0 = 0). Then, add the remaining numbers: (1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 0 + 1 = 11). Thus, the final result is 11.
simply 9
211-11=200
Binary sum 1001+101+11 = 10001Recall:0 + 0 = 00 + 1 = 01 + 0 = 01 + 1 = 10Start from the end:1 + 1 + 1 = 1 carry on 11 + 1 + 0 + 0 = 0 carry on 11 + 1 + 0 = 0 carry on 11 + 1 = 10or1001 = 23 + 20 = 8 + 1 = 9101 = 22 + 20 = 4 + 1 = 511 = 21 + 20 = 2 + 1 = 317 = 24 + 20 = 10001
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.