It is xD9 in hex. 1101 -> D (13 in base 10) and 1001 -> 9.
1101 1001 in binary is D9 in hex and 139 in decimal
In HEX, 1101 1001 is D9. Translated to decimal, that equals 217.
Binary 1101 = D
The next integer is 1101, but there is no next number.
(1234)hex=(0001 0010 0011 0100)2 (DA57)hex=(1101 1010 0101 0111)2 Taking, (1234)hex=(0001 0010 0011 0100)2 =(1110 1101 1100 1011) -1s complement =(1110 1101 1100 1100) -2s complement Now ,add 2s complement of (1234)hex with (DA57)hex, we get 1110 1101 1100 1100 + 1101 1010 0101 0111 1 1100 1000 0010 0011 There is a Carry bit Since,carry is generated.so,no is negative Then take 2s complement of above no.Thus ,we get 0011 0111 1101 1101=(37DD)hex (1234)hex -(DA57)hex =37DD)hex
a)5b39+39a2=101 1011 0011 1001+11 1001 1010 0010=1001 0100 1101 1011 af=0 sf=1 zf=0 cf=0 b)5b39+dc49=101 1011 0011 1001+1101 1100 0100 1001=1 0011 0111 1000 0010 af=1 sf=0 zf=0 cf=1
1110 0101 1101 1011 is E5DB
It is DAB not that hard really 0001 1 0010 2 0011 3 0100 4 0101 5 0110 6 0111 7 1000 8 1001 9 1010 A 1011 B 1100 C 1101 D 1110 E 1111 F and there you go
The binary number 11011001 relates in decimal to the number 221.
110110012 = 1101 10012 = [1310] [910] = D916
1101 => 11011 1010 => 10110 0011 => 10101 0001 => 01001 1000 => 10010 1001 => 10011 and together: 11011 10110 10101 01001 10010 10011
A nibble consists of 4 bits. The binary number "1011 1101 1001 1110" contains 16 bits in total. Therefore, to find the number of nibbles, you divide the total number of bits by 4, which results in 4 nibbles.