10 * M = 0.02
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M = 0.02 / 10
M = 0.002
(7.5 m) x (100 cm/m) x (10 mm/cm) = (7.5 x 100 x 10) = 7,500 mm
0.337 mm = 0.337 x 10^-3 = 0.337 x 0.001 = 0.000337 m or 3.37 x 10^-4 m.
x + 5y = 10 5y = -x + 10 y = -x/5 + 2 m = -1/5 or .2
13.7
Hint: 1 m = 10 dm... 59.2 m = 59.2 x 10 dm = 592 dm
1.0 x 10-12
2.115 x 10^-3 x 4.05 x 10^-5 = 8.56575 x 10^-8
1.39
in algabreic terms, it is x
If m equals 3 then m to the 6th power (m6) equals 36 or 3 x 3 x 3 or 27
m=8 l=6 y=4 m X m = 8 X 8 = 64 =ly m X l = 8 X 6 = 48 = ym
The pH level when [OH-] equals 2.3 x 10^-3 M can be calculated using the equation: pOH = -log[OH-]. Given [OH-] = 2.3 x 10^-3 M, pOH = -log(2.3 x 10^-3) ≈ 2.64. Since pH + pOH = 14, pH = 14 - pOH = 14 - 2.64 ≈ 11.36.