1111111111
o.1111111111 recurring
1,111,111,111
No, 1023 it is not one of the multiples of the base 2 (binary) system. 1024 is. 1024 = 210. Of course 1023 can be represented in base 2 however as 1111111111.
the options i can see are: 1111111111 111111112 11111122 1111222 112222 22222 there are 6 combinations but i will need to reformulate to work out how many permutations of these 6 combinations there are
1111111111 x 1111111111 = 1234567900987654321
1,234,567,900,987,654,321
open 5555555555/777777777777
123456790087654321
1111111111
1111111111
10/9
1111111111
1234
1.234567900987654e+18
Yes because it can be expressed as a fraction
o.1111111111 recurring