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How many ways can we make 21p using 1p 2p 5p?
There are 31 ways:1p × 211p × 19 + 2p × 11p × 17 + 2p × 21p × 16 + 5p × 11p × 15 + 2p × 31p × 14 + 2p × 1 + 5p × 11p × 13 + 2p × 41p × 12 + 2p × 2 + 5p × 11p × 11 + 2p × 51p × 11 + 5p × 21p × 10 + 2p × 3 + 5p × 11p × 9 + 2p × 61p × 9 + 2p × 1 + 5p × 21p × 8 + 2p × 4 + 5p1p × 7 + 2p × 71p × 7 + 2p × 2 + 5p × 21p × 6 + 2p × 5 + 5p1p × 6 + 5p × 31p × 5 + 2p × 81p × 5 + 2p × 3 + 5p × 21p × 4 + 2p × 6 + 5p × 11p × 4 + 2p × 1 + 5p × 31p × 3 + 2p × 91p × 3 + 2p × 4 + 5p × 21p × 2 + 2p × 7 + 5p × 11p × 2 + 2p × 2 + 5p × 31p × 1 + 2p × 101p × 1 + 2p × 5 + 5p × 21p × 1 + 5p × 42p × 8 + 5p × 12p × 3 + 5p × 3
How do you solve r equals 4q-5p over 9 solve for p?
Do you mean: r = (4q-5p)/9? If so then: p = (9r-4q)/-5
How many ways to make 20p usin 1p 2p and 5p coins?
29 Ways: 20(1p) 18(1p),1(2p) 16(1p),2(2p) 14(1p),3(2p) 12(1p),4(2p) 10(1p),5(2p) 8(1p),6(2p) 6(1p),7(2p) 4(1p),8(2p) 2(1p),9(2p) 10(2p) 4(5p) 3(5p),2(2p),1(1p) 3(5p),1(2p),3(1p) 3(5p),5(1p) 2(5p),5(2p) 2(5p),4(2p),2(1p) 2(5p),3(2p),4(1p) 2(5p),2(2p),6(1p) 2(5p),1(2p),8(1p) 2(5p),10(1p) 1(5p),7(2p),1(1p) 1(5p),6(2p),3(1p) 1(5p),5(2p),5(1p) 1(5p),4(2p),7(1p) 1(5p),3(2p),9(1p) 1(5p),2(2p),11(1p) 1(5p),1(2p),13(1p) 1(5p),15(1p)
What is the answer to 5p plus 14 equals 4p-1?
p=-15
How many ways can you make 40p with a 20p 10p and 5p?
9
How would you solve 5p - 14 equals 8p plus 4?
5p-14 = 8p +4 take the 14 to the other side and the 8p to the other side so 5p-8p = 4 +14 -3p = 18 p = -18/3
What is 5p pq-4pr?
9
What is 8 plus 5p plus 7q plus 9 plus 3p?
8 + 5p + 7q + 9 + 3p Reordering: 8 + 9 + 5p + 3p + 7q Combine like terms: 17 + 8p + 7q
How many ways can we make 21p using 1p 2p 5p?
There are 31 ways:1p × 211p × 19 + 2p × 11p × 17 + 2p × 21p × 16 + 5p × 11p × 15 + 2p × 31p × 14 + 2p × 1 + 5p × 11p × 13 + 2p × 41p × 12 + 2p × 2 + 5p × 11p × 11 + 2p × 51p × 11 + 5p × 21p × 10 + 2p × 3 + 5p × 11p × 9 + 2p × 61p × 9 + 2p × 1 + 5p × 21p × 8 + 2p × 4 + 5p1p × 7 + 2p × 71p × 7 + 2p × 2 + 5p × 21p × 6 + 2p × 5 + 5p1p × 6 + 5p × 31p × 5 + 2p × 81p × 5 + 2p × 3 + 5p × 21p × 4 + 2p × 6 + 5p × 11p × 4 + 2p × 1 + 5p × 31p × 3 + 2p × 91p × 3 + 2p × 4 + 5p × 21p × 2 + 2p × 7 + 5p × 11p × 2 + 2p × 2 + 5p × 31p × 1 + 2p × 101p × 1 + 2p × 5 + 5p × 21p × 1 + 5p × 42p × 8 + 5p × 12p × 3 + 5p × 3
How do you solve r equals 4q-5p over 9 solve for p?
Do you mean: r = (4q-5p)/9? If so then: p = (9r-4q)/-5
How many ways to make 20p usin 1p 2p and 5p coins?
29 Ways: 20(1p) 18(1p),1(2p) 16(1p),2(2p) 14(1p),3(2p) 12(1p),4(2p) 10(1p),5(2p) 8(1p),6(2p) 6(1p),7(2p) 4(1p),8(2p) 2(1p),9(2p) 10(2p) 4(5p) 3(5p),2(2p),1(1p) 3(5p),1(2p),3(1p) 3(5p),5(1p) 2(5p),5(2p) 2(5p),4(2p),2(1p) 2(5p),3(2p),4(1p) 2(5p),2(2p),6(1p) 2(5p),1(2p),8(1p) 2(5p),10(1p) 1(5p),7(2p),1(1p) 1(5p),6(2p),3(1p) 1(5p),5(2p),5(1p) 1(5p),4(2p),7(1p) 1(5p),3(2p),9(1p) 1(5p),2(2p),11(1p) 1(5p),1(2p),13(1p) 1(5p),15(1p)
What is the answer to 5p plus 14 equals 4p-1?
p=-15
How many ways to make 35p using 5p 10p 2p 1p and 20p coins?
It can be done in 162 ways, viz: 1 × 20p, 1 × 10p, 1 × 5p 1 × 20p, 1 × 10p, 2 × 2p, 1 × 1p 1 × 20p, 1 × 10p, 1 × 2p, 3 × 1p 1 × 20p, 1 × 10p, 5 × 1p 1 × 20p, 3 × 5p 1 × 20p, 2 × 5p, 2 × 2p, 1 × 1p 1 × 20p, 2 × 5p, 1 × 2p, 3 × 1p 1 × 20p, 2 × 5p, 5 × 1p 1 × 20p, 1 × 5p, 5 × 2p 1 × 20p, 1 × 5p, 4 × 2p, 2 × 1p 1 × 20p, 1 × 5p, 3 × 2p, 4 × 1p 1 × 20p, 1 × 5p, 2 × 2p, 6 × 1p 1 × 20p, 1 × 5p, 1 × 2p, 8 × 1p 1 × 20p, 1 × 5p, 10 × 1p 1 × 20p, 7 × 2p, 1 × 1p 1 × 20p, 6 × 2p, 3 × 1p 1 × 20p, 5 × 2p, 5 × 1p 1 × 20p, 4 × 2p, 7 × 1p 1 × 20p, 3 × 2p, 9 × 1p 1 × 20p, 2 × 2p, 11 × 1p 1 × 20p, 1 × 2p, 13 × 1p 1 × 20p, 15 × 1p 3 × 10p, 1 × 5p 3 × 10p, 2 × 2p, 1 × 1p 3 × 10p, 1 × 2p, 3 × 1p 3 × 10p, 5 × 1p 2 × 10p, 3 × 5p 2 × 10p, 2 × 5p, 2 × 2p, 1 × 1p 2 × 10p, 2 × 5p, 1 × 2p, 3 × 1p 2 × 10p, 2 × 5p, 5 × 1p 2 × 10p, 1 × 5p, 5 × 2p 2 × 10p, 1 × 5p, 4 × 2p, 2 × 1p 2 × 10p, 1 × 5p, 3 × 2p, 4 × 1p 2 × 10p, 1 × 5p, 2 × 2p, 6 × 1p 2 × 10p, 1 × 5p, 1 × 2p, 8 × 1p 2 × 10p, 1 × 5p, 10 × 1p 2 × 10p, 7 × 2p, 1 × 1p 2 × 10p, 6 × 2p, 3 × 1p 2 × 10p, 5 × 2p, 5 × 1p 2 × 10p, 4 × 2p, 7 × 1p 2 × 10p, 3 × 2p, 9 × 1p 2 × 10p, 2 × 2p, 11 × 1p 2 × 10p, 1 × 2p, 13 × 1p 2 × 10p, 15 × 1p 1 × 10p, 5 × 5p 1 × 10p, 4 × 5p, 2 × 2p, 1 × 1p 1 × 10p, 4 × 5p, 1 × 2p, 3 × 1p 1 × 10p, 4 × 5p, 5 × 1p 1 × 10p, 3 × 5p, 5 × 2p 1 × 10p, 3 × 5p, 4 × 2p, 2 × 1p 1 × 10p, 3 × 5p, 3 × 2p, 4 × 1p 1 × 10p, 3 × 5p, 2 × 2p, 6 × 1p 1 × 10p, 3 × 5p, 1 × 2p, 8 × 1p 1 × 10p, 3 × 5p, 10 × 1p 1 × 10p, 2 × 5p, 7 × 2p, 1 × 1p 1 × 10p, 2 × 5p, 6 × 2p, 3 × 1p 1 × 10p, 2 × 5p, 5 × 2p, 5 × 1p 1 × 10p, 2 × 5p, 4 × 2p, 7 × 1p 1 × 10p, 2 × 5p, 3 × 2p, 9 × 1p 1 × 10p, 2 × 5p, 2 × 2p, 11 × 1p 1 × 10p, 2 × 5p, 1 × 2p, 13 × 1p 1 × 10p, 2 × 5p, 15 × 1p 1 × 10p, 1 × 5p, 10 × 2p 1 × 10p, 1 × 5p, 9 × 2p, 2 × 1p 1 × 10p, 1 × 5p, 8 × 2p, 4 × 1p 1 × 10p, 1 × 5p, 7 × 2p, 6 × 1p 1 × 10p, 1 × 5p, 6 × 2p, 8 × 1p 1 × 10p, 1 × 5p, 5 × 2p, 10 × 1p 1 × 10p, 1 × 5p, 4 × 2p, 12 × 1p 1 × 10p, 1 × 5p, 3 × 2p, 14 × 1p 1 × 10p, 1 × 5p, 2 × 2p, 16 × 1p 1 × 10p, 1 × 5p, 1 × 2p, 18 × 1p 1 × 10p, 1 × 5p, 20 × 1p 1 × 10p, 12 × 2p, 1 × 1p 1 × 10p, 11 × 2p, 3 × 1p 1 × 10p, 10 × 2p, 5 × 1p 1 × 10p, 9 × 2p, 7 × 1p 1 × 10p, 8 × 2p, 9 × 1p 1 × 10p, 7 × 2p, 11 × 1p 1 × 10p, 6 × 2p, 13 × 1p 1 × 10p, 5 × 2p, 15 × 1p 1 × 10p, 4 × 2p, 17 × 1p 1 × 10p, 3 × 2p, 19 × 1p 1 × 10p, 2 × 2p, 21 × 1p 1 × 10p, 1 × 2p, 23 × 1p 1 × 10p, 25 × 1p 7 × 5p 6 × 5p, 2 × 2p, 1 × 1p 6 × 5p, 1 × 2p, 3 × 1p 6 × 5p, 5 × 1p 5 × 5p, 5 × 2p 5 × 5p, 4 × 2p, 2 × 1p 5 × 5p, 3 × 2p, 4 × 1p 5 × 5p, 2 × 2p, 6 × 1p 5 × 5p, 1 × 2p, 8 × 1p 5 × 5p, 10 × 1p 4 × 5p, 7 × 2p, 1 × 1p 4 × 5p, 6 × 2p, 3 × 1p 4 × 5p, 5 × 2p, 5 × 1p 4 × 5p, 4 × 2p, 7 × 1p 4 × 5p, 3 × 2p, 9 × 1p 4 × 5p, 2 × 2p, 11 × 1p 4 × 5p, 1 × 2p, 13 × 1p 4 × 5p, 15 × 1p 3 × 5p, 10 × 2p 3 × 5p, 9 × 2p, 2 × 1p 3 × 5p, 8 × 2p, 4 × 1p 3 × 5p, 7 × 2p, 6 × 1p 3 × 5p, 6 × 2p, 8 × 1p 3 × 5p, 5 × 2p, 10 × 1p 3 × 5p, 4 × 2p, 12 × 1p 3 × 5p, 3 × 2p, 14 × 1p 3 × 5p, 2 × 2p, 16 × 1p 3 × 5p, 1 × 2p, 18 × 1p 3 × 5p, 20 × 1p 2 × 5p, 12 × 2p, 1 × 1p 2 × 5p, 11 × 2p, 3 × 1p 2 × 5p, 10 × 2p, 5 × 1p 2 × 5p, 9 × 2p, 7 × 1p 2 × 5p, 8 × 2p, 9 × 1p 2 × 5p, 7 × 2p, 11 × 1p 2 × 5p, 6 × 2p, 13 × 1p 2 × 5p, 5 × 2p, 15 × 1p 2 × 5p, 4 × 2p, 17 × 1p 2 × 5p, 3 × 2p, 19 × 1p 2 × 5p, 2 × 2p, 21 × 1p 2 × 5p, 1 × 2p, 23 × 1p 2 × 5p, 25 × 1p 1 × 5p, 15 × 2p 1 × 5p, 14 × 2p, 2 × 1p 1 × 5p, 13 × 2p, 4 × 1p 1 × 5p, 12 × 2p, 6 × 1p 1 × 5p, 11 × 2p, 8 × 1p 1 × 5p, 10 × 2p, 10 × 1p 1 × 5p, 9 × 2p, 12 × 1p 1 × 5p, 8 × 2p, 14 × 1p 1 × 5p, 7 × 2p, 16 × 1p 1 × 5p, 6 × 2p, 18 × 1p 1 × 5p, 5 × 2p, 20 × 1p 1 × 5p, 4 × 2p, 22 × 1p 1 × 5p, 3 × 2p, 24 × 1p 1 × 5p, 2 × 2p, 26 × 1p 1 × 5p, 1 × 2p, 28 × 1p 1 × 5p, 30 × 1p 17 × 2p, 1 × 1p 16 × 2p, 3 × 1p 15 × 2p, 5 × 1p 14 × 2p, 7 × 1p 13 × 2p, 9 × 1p 12 × 2p, 11 × 1p 11 × 2p, 13 × 1p 10 × 2p, 15 × 1p 9 × 2p, 17 × 1p 8 × 2p, 19 × 1p 7 × 2p, 21 × 1p 6 × 2p, 23 × 1p 5 × 2p, 25 × 1p 4 × 2p, 27 × 1p 3 × 2p, 29 × 1p 2 × 2p, 31 × 1p 1 × 2p, 33 × 1p 35 × 1p
How many ways can you make 40p with a 20p 10p and 5p?
9
What is 2p - 9 equals 5p plus 12?
2p - 9 = 5p + 12 subtract 2p fom both sides -9 = 3p +12 subtract 12 from both sides -21 = 3p divide both sides by 3 -7 = p
Pencils cost 5p each How much would 14 pencils cost?
Costs 70p
What is the maximum number of electrons each of the following can hold... 2s 5p 4f 3d 4d?
2s: 2 electrons 5p: 6 4f: 14 3d: 10 4d: 10
