43
3 times ! 14 plus 14 plus 14 OR 14 times 3 !
115
1 3/4 x 8 = 14 working out is 1 x 8 = 8 1 x 3/4 = 6 add them together = 14
3.5 times 4 = 14 4 and 2/3 times 3 = 14 and of course...... 1 times 14 = 14
(1/7) + (3/14) = (2/14) + (3/14) = 5/14
17
That is the way that it comes out.
5/14 * 21/35 = 5/14 * 3/5 = 1/14 * 3/1 = 3/14
14 times 7 is 98
14 x 1/6 = 21/3
3/14
The sequence 2, 5, 14, 41, 122 appears to follow a pattern where each term is generated by multiplying the previous term by 3 and then adding 1, starting with 2. Specifically, the calculations are as follows: (2 \times 3 + 1 = 5), (5 \times 3 - 1 = 14), (14 \times 3 - 1 = 41), and (41 \times 3 - 1 = 122). This rule can be expressed as (a_n = 3a_{n-1} - 1) for (n > 1).