It is: 2*3*3*7*13 = 1638 or as 2*32*7*13 = 1638
The prime factors of 1,638 are: 2 3 7 13As a product of its prime factors: 2*3*3*7*13 = 1638
no because it ends with an 8 any # that ends with an even integer is reducible
It is simply the whole number written as the product of its prime factors.It is simply the whole number written as the product of its prime factors.It is simply the whole number written as the product of its prime factors.It is simply the whole number written as the product of its prime factors.
The product of two prime numbers is always a composite number, and it never is a prime number.
To find the prime factors of a number, start with any 2 factors and keep factoring the composite factors until all are prime. 1638 2 x 819 2 x 3 x 273 2 x 3 x 3 x 91 2 x 3 x 3 x 7 x 13 = 1638
No, it cannot be written as the product of prime number as a prime number is a number having factors 1 and itself.
The product of the prime factors of a number is the number itself.
A number as a product of prime numbers would be "x".
Prime factorization is writing a composite number as a product of prime numbers.
A composite number is the product of two or more prime numbers.
Showing a composite number as a product of prime numbers is called prime factorization.