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What is 1776 plus 999 added in two different ways and 1776 minus 999 subtracted in two different ways but working out all four calculations entirely in Roman numerals with explanations?
Wiki User
∙ 8y ago
The rules as we know them today now governing the Roman numerals system had nothing to do with the Romans because they were introduced during the Middle Ages and as result of these rules the equivalent of 999 converted into Roman numerals is now considered to be CMXCIX which hardly lends itself quite easily for the purpose of mathematical operations but there exist credible evidence to show that the ancient Romans would have worked out the requested calculations as in the following formats:-
MDCCLXXVI+IM = MMDCCLXXV => 1776+(1000-1) = 2775
MDCCLXXVI+DCCCCLXXXXVIIII = MMDCCLXXV => 1776+999 = 2775
MDCCLXXVI-IM = DCCLXXVII => 1776-(1000-1) = 777
MDCCLXXVI-DCCCCLXXXXVIIII = DCCLXXVII => 1776-999 = 777
Note that in mathematics -(1000-1) becomes 1-1000 and that the above calculations were fairly simple and straightforward to work out but for more advanced calculations the Romans would have used an abacus calculating device.
QED
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∙ 8y ago
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How would you actually add together 1666 and 1999 in two different ways entirely in Roman numerals throughout both calculations with explanations?
See answer to question: ' How do you add together 1666 and 1999 in two different ways using Roman numerals'
How would you work out 1776 plus 549 in two different ways and 1776 minus 549 in two different ways but working out all four calculations entirely in Roman numerals with explanations?
Roman numerals are entirely inappropriate for doing such calculations. I believe the people in Roman times did such calculations on an abacus or something similar - which is basically similar to converting them to the Arabic numbers we use. If you really want to do it in Roman numerals - which is basically NOT a good idea - you would have to keep the thousands, hundreds, etc. separate, and handle carry (for addition) and borrowing (for subtraction).
What is 1776 plus 89.5 added in two different ways and 1776 minus 89.5 subtracted in two different ways entirely in Roman numerals with explanations?
The rules now governing the Roman numeral system as we know them today had nothing to do with the Romans because they were introduced during the Middle ages but there exist credible evidence to show that the ancient Romans would have worked out all four calculations in the following formats:-MDCCLXXVI+SXC = MDCCCLXVS => 1776+(100-10.5) = 1865.5MDCCLXXVI+LXXXVIIIIS = MDCCCLXVS => 1776+89.5 = 1865.5MDCCLXXVI-SXC = MDCLXXXVIS => 1776-(100-10.5) = 1686.5MDCCLXXVI-LXXXVIIIIS = MDCLXXXVIS => 1776-89.5 = 1686.5Note that in mathematics -(100-10.5) becomes 10.5-100 and that the above calculations were fairly simple and straightforward to work out but for more complicated calculations the Romans would have used an abacus calculating device.QED
What is 1218 plus 558 added in two different ways and 1218 minus 558 subtracted in two different ways but working out all four calculations entirely in Roman numerals with explanations?
The following answers are self explanatory:-IIMCCXX+IIDLX = MDCCLXXVI => (1220-2)+(560-2) = 1776MCCXVIII+DLVIII = MDCCLXXVI => 1218+558 = 1776IIMCCXX-IIDLX = DCLX => (1220-2)-(560-2) = 660MCCXVIII-DLVIII = DCLX => 1218-558 = 660Note that the rules as we now know them today governing the Roman numeral system had little or nothing to do with the ancient Romans whatsoever because they were introduced during the Middle Ages and so therefore the Romans would have probably worked out the given simple calculations as shown above but for more complicated calculations the Romans would have made usage of an abacus calculating device.QED
What is 1776 plus 249 added in two different ways and 1776 minus 249 subtracted in two different ways but working out all four calculations entirely in Roman numerals with explanations?
Under today's modern rules now governing the Roman numeral system the equivalent of 249 when converted into Roman numerals is now considered to be CCXLIX which does not lend itself quite easily to arithmetical operations but there exist credible evidence to suggest that the ancient Romans would have carried out the requested calculations as follows:-MDCCLXXVI+ICCL = MMXXV => 1776+(250-1) = 2025MDCCLXXVI+CCXXXXVIIII = MMXXV => 1776+249 = 2025MDCCLXXVI-ICCL = MDXXVII => 1776-(250-1) = 1527MDCCLXXVI-CCXXXXVIIII = MDXXVII => 1776-249 = 1527Note that in mathematics -(250-1) becomes -250+1 or as 1-250The above calculations were fairly simple and straight forward to work out but for more complicated calculations the Romans would make use of an abacus calculating device.QED
What is 1000 -900 -80 -9 subtracted in two different ways but working out both calculations from start to finish entirely in Roman numerals with explanations?
The rules as we now know then today governing the Roman numeral system has and had absolutely nothing to do with the Romans whatsoever because they were introduced during the Middle Ages long after the collapse of the Roman Empire but we can extrapolate from historic sources that the ancient Romans would have almost in all probability subtracted the given numbers in either of the following formats:-DCCCCLXXXXX-DCCCC-LXXX-VIIII = XI => 1000-900-80-9 = 11M-(-C+M)-LXXX-(-I+X) = XI => 1000-(-100+1000)-80-(-I+10) = 11Note that in mathematics that -(-C+M) becomes C-M or that -(-100+1000) becomes 100-1000 and for more complicated calculations the Romans would have made usage of an abacus calculating device.QED
What is 28 plus 22 added in two different ways and 28 minus 22 subtracted in two different ways but working out all four calculations entirely in Roman numerals with explanations?
The rules as we now know them today governing the Roman numeral system has and had absolutely nothing to do with the ancient Romans whatsoever because the present rules were introduced during the Middle Ages but notwithstanding the aforementioned inasmuch that there exist credible evidence to show that the Romans would have worked out the required calculations as in the following formats:-IIXXX+XXII = L => (30-2)+22 = 50XXVIII+XXII = L => 28+22 = 50IIXXX-XXII = VI => (30-2)-22 = 6XXVIII-XXII = VI => 28-22 = 6Latin was the ancient language spoken by the Romans and the Latin word for IIXXX is 'duodetriginta' which literately means two from thirty and furthermore the above calculations were fairly simple and straightforward to work out but for more complicated calculations the Romans would have made usage of an abacus calculating device.QED
How would you work out 1776 plus 9 in two different ways and 1776 minus 9 in two different ways but working out all four calculations entirely in Roman numerals with explanations?
When 9 is converted into Roman numerals it is IX which is an abridged version of VIIII and so the required calculations are as follows:-MDCCLXXVI+IX = MDCCLXXXV => 1776+(10-1) = 1785MDCCLXXVI+VIIII = MDCCLXXXV => 1776+9 = 1785MDCCLXXVI-IX = MDCCLXVII => 1776-(10-1) = 1767MDCCLXXVI-VIIII = MDCCLXVII => 1776-9 = 1767Note that in mathematics -(10-1) changes to 1-10QED
What is 89.5 plus 18.5 added in two different ways and 89.5 minus 18.5 subtracted in two different ways but working out all four calculations entirely in Roman numerals with explanations?
The rules as we know them today now governing the Roman numeral system had nothing to do with the Romans because they were introduced during the Middle Ages but there exist credible evidence to suggest that the ancient Romans would have worked out the requested calculations as follows:SXC+SIXX = CVIII => (100-10.5)+(20-1.5) = 108LXXXVIIIIS+XVIIIS = CVIII => 89.5+18.5 = 108SXC-SIXX = LXXI => (100-10.5)-(20-1.5) = 71LXXXVIIIIS-XVIIIS = LXXI => 89.5-18.5 = 71Information extracted from: 'History of Mathematics' volume 2 by David Eugene Smith first published in 1925 and ISBN 0486 204 308.QED by David Gambell
What is the sum of 1999 and 2014 added together in two different ways entirely in Roman numerals with explanations?
MIM + MMXIV = MMMXIII or MMCXCIX + MMXIII = MMMXIII There is only one way to write the solution (3013)
What is 1999 plus 666 added in two different ways and 1999 minus 666 subtracted in two different ways but working out all four calculations entirely in Roman numerals with explanations?
The rules as we know them today now governing the Roman numeral system had absolutely nothing to do with the Romans because they were introduced during the Middle Ages and as a result of these rules the equivalent of 1999 when converted into Roman numerals is now considered to be MCMXCIX which hardly lends itself quite easily for the purpose of mathematical operations but notwithstanding the aforementioned inasmuch that there exist credible evidence to support the premiss that the ancient Romans would have carried out the requested calculations as in the following formats:-MDCCCCLXXXXVIIII+DCLXVI = MMDCLXV => 1999+666 = 2665IMM+DCLXVI = MMDCLXV => (2000-1)+666 = 2665MDCCCCLXXXXVIIII-DCLXVI = MCCCXXXIII => 1999-666 = 1333IMM-DCLXVI is the same as the above because IMM = MDCCCCLXXXXVIIIIFor more intricate and complicated calculations the Romans would have made use of an abacus calculating device.QED by David Gambell
How would you add together 51 plus 49 in two different ways and 51 minus 49 in two different ways but showing all calculations entirely in Roman numerals with explanations?
Doing arithmetic with Roman numerals is exasperating, and imho a pointless waste of time, except to demonstrate the obvious superiority of our "normal numbers," which use base-10 radix / positional notation that includes a zero digit as a placeholder. I'd venture to say science & technology -- commerce, too -- could never have developed in recent centuries if we still used Roman numerals for calculations. However, this web site explains some methods: http://turner.faculty.swau.edu/mathematics/materialslibrary/roman/
