232 ÷ 8 = 29
232 + 1 = 233
int main (void){puts ("1 232 34543 232 1");return 0;} int main (void){ puts ("1 232 34543 232 1"); return 0; }
232 and 1 yay!
These are all the divisors of 232: 1, 2, 4, 8, 29, 58, 116, 232
2 1 232 116 4 8 Just a few
1 and 2 are the only common factors for 110 and 232.
You would need 20 twos to number the pages from 1 to 232. This is because there are 20 occurrences of the digit two in the numbers from 1 to 232.
1 2 4 8 29 58 116 and 232.
1, 2, 4, 8, 29, 58, 116, 232.
1, 2, 4, 8, 29, 58, 166, 232
1, 2, 4, 8, 29, 58, 116, 232.
1, 2, 4, 8, 29, 58, 116, 232