Q: What is 1 plus 3z equals?

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Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7

x, y and z are the variables.

-47 + 6z = 3z-2-3z -3z-47 + 3z = -2+47 +473z = 45/3 /3z = 15

Collect all the letters on one side and the numbers on the other; what you do to one side of the equals you do to the other: 3z + 2 = 6z - 13 → 3z +2 - 3z = 6z - 13 - 3z → 2 = 3z - 13 → 2 + 13 = 3z - 13 + 13 → 15 = 3z → 3z = 15 (this is just changing the equals around so that the letter is on the left) → 3z ÷ 3 = 15 ÷ 5 → z = 5

-3z+17+12z = 11 9z = -6 z = -2/3

-6z 2 = 3z+ 4z+28 -6z+2 +3z = 3z+ 4z +28 +4z -6z+4z+2 = 3z+ 28 -10z+2 -3z= 28 - 2 -10z + -3z = 26 -13z/13 = 26/-13 z = -2

It works out that: z = -32

9z+8 = 3z-10 9z-3z = -10-8 6z = -18 z = -3

If you mean: (3z/7) +9 = -7 then the value of z works out as -37 and 1/3

13y+3z+8

Im guessing that the equation is 7x - 2y +3z= 19 so the answer is 7x + 3z= 19

Here's your problem: 3z + 7 = 4z Next, you need to put all of the z's on one side. So you would do this: 3z (-3z) + 7 = 4z (+3z) And you will get this: 7 = 7z Then you will divide each side by 7 in order to find z. (7/7 = 7z/7) The answer will be 1 = z.

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its 10x +9y +1z

15 = 3z - 6 15 + 6 = 3z 3z = 21 z = 7

It is a singular matrix.

It's rare to see an equation with two equals signs. I'm guessing something else went in between 3z and 9. 3z + 9 = 15, then z = 2 3z - 9 = 15, then z = 8 3z x 9 = 15, then z = 5/9 3z/9 = 15, then z = 45

3z + 8 + 2z + 6 = 5z + 14

-6z + 2 = 3z + 4z + 28 Add 6z to both sides: 2 = 3z + 4z + 28 + 6z = 28 + 13z Subtract 28 from both sides: - 26 = 13z Divide both sides by 13: -2 = z

4.34684352143

5x-2y+3z-2x-y-4z=3x-3y-z

The ordered triple is (x, y, z) = (1, -1, -2)

3x + 3 (y-z)

8x + 5z - 4x + 3z + 6 = 8x - 4x + 5z + 3z - 6 = 4x + 8z - 6

Solve this system of equations. 5x+3y+z=-29 x-3y+2z=23 14x-2y+3z=-18 Write the solution as an ordered triple.