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Combine 8x plus 5z minus 4x plus 3z plus 6?
8x + 5z - 4x + 3z + 6 = 8x - 4x + 5z + 3z - 6 = 4x + 8z - 6
2x - 2y plus 5z - 2x - y plus 3z simplify?
well, this is pretty easy, just look at it logically:2x - 2y + 5z - 2x - y + 3zwhen you are trying to simplify a formula, your best practice would be to always begin with "organizing" the numbers, in this case it would become:2x - 2x -2y - y + 5z +3zwhen you organize it, it becomes clear what you need to do; first you get rid of the "opposing" values which cancel each other out, in this case the 2x:2x - 2x -2y - y + 5z +3z = -2y - y + 5z + 3zWhen two numbers have the exact same values but one is positive and the other is negative, their result is always zero, so you can simply erase them. In the opposite, when both of them are positive or both of them are negative, then they add up to each other:-2y - y + 5z +3z = -3y + 8z OR 8z - 3yFor this one, I don't think it can be simplified further, 8z - 3y is its' simplest form.
What is the answer to -8z plus 12 equals 12 - 4z?
-8z + 12 = 12 - 4z-8z +4z + 12 = 12 - 4z +4z-4z + 12 -12 = 12 -12-4z / -4 = 0 / -4z = 0:)
What is 8z to the 2nd power - 64?
I assume you mean... 8Z^2 - 64 = 0 8Z^2 = 64 Z^2 = 8 Z = sqrt(8) ( which can be factored and expressed.... ) Z = 2sqrt(2)
If 15x's equals 20y's and 16y's equals 10z's then 6x's equals how many z's?
To solve this problem, we first need to establish the relationship between x, y, and z. From the given information, we have 15x = 20y and 16y = 10z. To find the relationship between x and z, we can substitute y from the first equation into the second equation. By doing this, we get 16(15/20)x = 10z, which simplifies to 12x = 10z. Therefore, 6x would equal 5z.
