210 7x3=21x10=210
21 multiply by 10 = 210
25-4=21 21x10=210 210+(4-1)= 213 doesnt use the 6 though
no dude u got that so rong its not 120 its 3x7=21x10=210 30x7=210 lol fail kid XD
210 = 21x10 = (3x7)(2x5) = 2x3x5x7. The following sets of factors all fit the conditions of the question: 2,3,5,7; 5,6,7; 2,7,15; 2,3,35; 3,10,7; 2,5,21 and 3,5,14.
31 x 7 --- __7 21 (The underscores are for formatting) The 7 should be aligned in a column to the right of 21 217 Or: 31 = 3x10 + 1 ---> 7 x (3x10 + 1) = 7x3x10 + 7x1 = 21x10 + 7 = 210 + 7 = 217
21 ft*10 ft*2 in = 21 ft*10 ft * (1/6) ft = 21*10/6 cu ft = 35 cu ft.
Improve 21x1=21 21x2=42 21x3=63 21x4=84 21x5=105 21x6=126 21x7=147 21x8=168 21x9=189 21x10=210
Charges are quantized. This means that they have quantities. Therefore, q=ne. q is the the charge, n is the number of electrons you are trying to find, and e is the charge on the electron. Remember that your given charge is in micro coulombs, and you'll have to turn that into coulombs. -21x10^-6 c/1.6X10^-19c =n, this will give you the number of extra electrons. hope this helps!
876 divided by 21. You can use your knowledge of the base 10 system to say: 21X10=210(too small) 21X20=420(still too small) 21X30=630(let me subtract 876-630=246, I'm getting close) 21X40=840 and when I subtract I get a remainder of 36. I can make 1 more group of 21. 36-21=15. So my answer is 41 with a remainder of 15. You can use multiples of 100,100, etc. for larger numbers.
The multiples of 21 up to 500 are as follows: 21x1=21 21x2=42 21x3=63 21x4=84 21x5=105 21x6=126 21x7=147 21x8=168 21x9=189 21x10=210 21x11=231 21x12=252 21x13=273 21x14=294 21x15=315 21x16=336 21x17=357 21x18=378 21x19=399 21x20=420 21x21=441 21x22=462 21x23=483 21x24=504