31
x 7
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__7
21 (The underscores are for formatting) The 7 should be aligned in a column to the right of 21
217
Or: 31 = 3x10 + 1 ---> 7 x (3x10 + 1) = 7x3x10 + 7x1 = 21x10 + 7 = 210 + 7 = 217
31 multiplied by 7 is 217
31
961
7 multiplied by 5 is 35. 7 multiplied by 5 = 35
To solve this problem, we first calculate the sum of 24 and 7, which is 31. Then, we find the difference between 18 and 6, which is 12. Finally, we multiply these two results together: 31 x 12 = 372. Therefore, the product of the sum of 24 and 7 multiplied by the difference of 18 and 6 is 372.
7 x 31
31 multiplied by 7 is 217
31
How about: 2*31 = 62
7 x 30 = 210
961
37 to base 8 is (24+7) = 31 in decimal 7 to base 8 is 7 in decimal Multiplying 31 by 7 = 217 in decimal and this is 331 in octal on base 8
4 goes into 31 a total of 7 times because 4 multiplied by 7 equals 28, which is the largest multiple of 4 that is less than 31. When you divide 31 by 4, you get a quotient of 7 with a remainder of 3. Thus, 4 fits into 31 seven full times.
24 goes into 31 once with a remainder of 7. This can be calculated by dividing 31 by 24, which equals 1 with a remainder of 7. In other words, 24 multiplied by 1 is 24, and adding the remainder of 7 gives the original number 31.
15.50 * 31 = 480.5
7 multiplied by 5 is 35. 7 multiplied by 5 = 35
To solve this problem, we first calculate the sum of 24 and 7, which is 31. Then, we find the difference between 18 and 6, which is 12. Finally, we multiply these two results together: 31 x 12 = 372. Therefore, the product of the sum of 24 and 7 multiplied by the difference of 18 and 6 is 372.