2*(n - 22) = n + 62n - 44 = n + 6n - 44 = 6n = 502*(n - 22) = n + 62n - 44 = n + 6n - 44 = 6n = 502*(n - 22) = n + 62n - 44 = n + 6n - 44 = 6n = 502*(n - 22) = n + 62n - 44 = n + 6n - 44 = 6n = 50
Yes.
44 2 22 2 11
1&44 2&22 4&11
Start by dividing 44 by 2 to get 22. Therefore, 22 + 22 = 44. If we subtract 1 from one number, and add 1 to the other number, the sum will be the same, but now using two consecutive odd numbers; ie, 21 + 23 = 44. Therefore, the smaller number is 21.
half 44 = 22
Since 44 is a multiple of 22, it is automatically the LCM.
2*(n - 22) = n + 62n - 44 = n + 6n - 44 = 6n = 502*(n - 22) = n + 62n - 44 = n + 6n - 44 = 6n = 502*(n - 22) = n + 62n - 44 = n + 6n - 44 = 6n = 502*(n - 22) = n + 62n - 44 = n + 6n - 44 = 6n = 50
Yes.
How about: 44/2 = 22 as an example
22, 44, 66, 88 and so on.
It can be. 22 is a proper factor of 44.
1, 2, 4, 11, 22, 44.
44 2 22 2 11
Any multiple of 22. 22, 44, 66 and so on.
1, 2, 4, 11, 22, 44
1&44 2&22 4&11