1, 2, 4, 11, 22, 44.
The divisors of 75 are 1,3,5,15,25 and 75 The divisors of 1394 are 1,2,4,17,34,41,82,697 and 1394 so apart from 1 they have no divisors in common and this means that the base improper fraction 1394/75 can not be simplified. Therefore 1397/75 = 18 with a remainder of 44 Th divisors of 44 are 1,2,4,11,22 and 44 So 75 and 44 have no divisors (except 1) in common and this means the the base proper fraction of 44/75 can not be simplified. So the complex number is 18 and 44/75
No. It's proper divisors, which are 1, 2, 4, 11 and 22, when added together are less than 44 itself.
44 has six divisors (factors): 1, 2, 4, 11, 22, 44.
There are eight divisors of the number 195.
The divisors (factors) of 44 are: 1, 2, 4, 11, 22, 44.
9/44 is already in its simplest form, because the only integral divisors of 9 are 1, 3, and 9; 3 and 9 are not integral divisors of 44; and division by 1 does not affect the form.
23 is a prime number. It has two divisors.
A perfect number equals the sum of its proper divisors. A deficient number is greater than the sum of its proper divisors. An abundant number is less than the sum of its proper divisors. Proper divisors of a number do not include the number itself.
The first number to have exactly 10 divisors is 48.
The divisors of 97 are: 1, 97.
15.6667
12 divisors: 1 2 4 5 10 11 20 22 44 55 110 220.