23 x 10 = 230
Something = 23/10 = 2.3
2.3 x 10 = 23
8.45 x 10^23 = 845,000,000,000,000,000,000,000
There are (6.023 \times 10^{23}) atoms in 1 mole of any substance (Avogadro's number). Therefore, there are (1.004 \times 6.023 \times 10^{23} \approx 6.05 \times 10^{23}) atoms in 1.004 moles of bismuth.
100,000,000,000,000,000,000,000
23 000. This is standard form and should be written as: 23 x 10^2. (The ^ denotes an exponent.)
Three out of 10 students speak Chinese.
700 ÷ 23 = 30 with remainder 10.
There are (6.022 \times 10^{23}) atoms in one mole of carbon. Therefore, in (1.0 \times 10^{-4}) moles of carbon, there would be (6.022 \times 10^{23} \times 1.0 \times 10^{-4} = 6.022 \times 10^{19}) carbon atoms.
5*23*2 = 23*5*2 (commutative property)= 23*(5*2) (associative property) = 23*10 = 230.
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