Something = 23/10 = 2.3
2.3 x 10 = 23
8.45 x 10^23 = 845,000,000,000,000,000,000,000
There are (6.023 \times 10^{23}) atoms in 1 mole of any substance (Avogadro's number). Therefore, there are (1.004 \times 6.023 \times 10^{23} \approx 6.05 \times 10^{23}) atoms in 1.004 moles of bismuth.
100,000,000,000,000,000,000,000
23 000. This is standard form and should be written as: 23 x 10^2. (The ^ denotes an exponent.)
Three out of 10 students speak Chinese.
There are (6.022 \times 10^{23}) atoms in one mole of carbon. Therefore, in (1.0 \times 10^{-4}) moles of carbon, there would be (6.022 \times 10^{23} \times 1.0 \times 10^{-4} = 6.022 \times 10^{19}) carbon atoms.
5*23*2 = 23*5*2 (commutative property)= 23*(5*2) (associative property) = 23*10 = 230.
There are (~6.022 \times 10^{23}) atoms in one mole of sulfur. Therefore, in 3 moles of sulfur there are (~3 \times 6.022 \times 10^{23} \approx 1.807 \times 10^{24}) atoms of sulfur.
1 mole contains 6.023 times 10^23 atoms....so ......2 moles ...that would be 2 times 6.023 times 10^23 got it?
1 centimeter = 10 millimeters 23 centimeters = (23 times 10) = 230 millimeters